In a redox reaction, electron could be lost or gained. The coefficients in the balanced redox reaction are; 1/2, 5, 1, 5, 2, 1.
<h3>What is a redox reaction equation?</h3>
A redox reaction equation shows the species that were oxidized or reduced in a redox reaction. In this case, we are asked for the coefficients in a balanced redox reaction equation.
We must recall that five electrons were lost/gained in the process hence the balanced reaction equation is;
1/2I2 + 5HNO3 -----> IO3^- + 5NO2 + 2H2O + H^+
The coefficients in the balanced equation therefore are; 1/2, 5, 1, 5, 2, 1.
Learn more about redox reaction: brainly.com/question/13293425
Answer: The most likely partial pressures are 98.7MPa for NO₂ and 101.3MPa for N₂O₄
Explanation: To determine the partial pressures of each gas after the increase of pressure, it can be used the equilibrium constant Kp.
For the reaction 2NO₂ ⇄ N₂O₄, the equilibrium constant is:
Kp = 
where:
P(N₂O₄) and P(NO₂) are the partial pressure of each gas.
Calculating constant:
Kp = 
Kp = 0.0104
After the weights, the total pressure increase to 200 MPa. However, at equilibrium, the constant is the same.
P(N₂O₄) + P(NO₂) = 200
P(N₂O₄) = 200 - P(NO₂)
Kp = 
0.0104 = ![\frac{200 - P(NO_{2}) }{[P(NO_{2} )]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B200%20-%20P%28NO_%7B2%7D%29%20%20%7D%7B%5BP%28NO_%7B2%7D%20%29%5D%5E%7B2%7D%7D)
0.0104
+
- 200 = 0
Resolving the second degree equation:
=
= 98.7
Find partial pressure of N₂O₄:
P(N₂O₄) = 200 - P(NO₂)
P(N₂O₄) = 200 - 98.7
P(N₂O₄) = 101.3
The partial pressures are
= 98.7 MPa and P(N₂O₄) = 101.3 MPa
Answer:
The only one that makes sense IF the model behaves as the Earth is D.
Explanation: