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iris [78.8K]
3 years ago
9

A buffer solution contains 0.20 mol of propionic acid (CH3CH2COOH) and 0.25 mol of sodium propionate (CH3CH2COONa) in 1.50 dm3.

Chemistry
1 answer:
const2013 [10]3 years ago
6 0

Answer:

I don't know how to do it the subject

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When the following redox equation is balanced with smallest whole number coefficients, the coefficient for nitrogen dioxide will
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In a redox reaction, electron could be lost or gained. The coefficients in the balanced redox reaction are;  1/2, 5, 1, 5, 2, 1.

<h3>What is a redox reaction equation?</h3>

A redox reaction equation shows the species that were oxidized or reduced in a redox reaction. In this case, we are asked for the coefficients in a balanced redox reaction equation.

We must recall that five electrons were lost/gained in the process hence the balanced reaction equation is;

1/2I2 + 5HNO3 -----> IO3^- + 5NO2 + 2H2O + H^+

The coefficients in the balanced equation therefore are; 1/2, 5, 1, 5, 2, 1.

Learn more about redox reaction: brainly.com/question/13293425

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A container has a mixture of NO2 gas and N2O4 gas in equilibrium. The chemical reaction between the two gases is described by th
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Answer: The most likely partial pressures are 98.7MPa for NO₂ and 101.3MPa for N₂O₄

Explanation: To determine the partial pressures of each gas after the increase of pressure, it can be used the equilibrium constant Kp.

For the reaction 2NO₂ ⇄ N₂O₄, the equilibrium constant is:

Kp = \frac{P(N_{2}O_{4} )}{P(NO_{2} ^{2}) }

where:

P(N₂O₄) and P(NO₂) are the partial pressure of each gas.

Calculating constant:

Kp = \frac{38.8}{61.2^{2} }

Kp = 0.0104

After the weights, the total pressure increase to 200 MPa. However, at equilibrium, the constant is the same.

P(N₂O₄) + P(NO₂) = 200

P(N₂O₄) = 200 - P(NO₂)

Kp = \frac{P(N_{2}O_{4} )}{P(NO_{2} ^{2}) }

0.0104 = \frac{200 - P(NO_{2})  }{[P(NO_{2} )]^{2}}

0.0104[P(NO_{2} )]^{2} + P(NO_{2} ) - 200 = 0

Resolving the second degree equation:

P(NO_{2} ) = \frac{-1+\sqrt{9.32} }{0.0208}

P(NO_{2} ) = 98.7

Find partial pressure of N₂O₄:

P(N₂O₄) = 200 - P(NO₂)

P(N₂O₄) = 200 - 98.7

P(N₂O₄) = 101.3

The partial pressures are P(NO_{2} ) = 98.7 MPa and P(N₂O₄) = 101.3 MPa

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