At critical temperature, the resistivity of the superconductor
B. It suddenly drops to zero
Explanation:
Materials can be classified into three different types depending on their resistance:
- Conductors: these materials have generally low resistance and allow electricity to pass through easily. The resistance of a conductor increases linearly with the temperature
- Insulators: these materials do not allow electricity to pass through - so they have very high resistance
- Semi-conductors: these are materials that are insulators are room temperature, however they becomes conductors when heated. Therefore, the resistance of a semiconductor decreases when the temperature increases
- Superconductors: these are special materials that are normally conductors; however, at very low temperatures (we are talking about temperature very near to 0 K), their resistance becomes suddenly zero.
Therefore, the correct answer is:
B. It suddenly drops to zero
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The correct answer for the question that is being presented above is this one:
Phi = BAsin(theta)
<span>1. Phi(i) = BA </span>
<span>2. Phi(f) = 0 </span>
3. EMF = N(phi(i)-phi(f))/deltat
Here are the follow-up questions:
<span>1. What is the total magnitude Phi_initial of the magnetic flux through the coil before it is rotated? </span>
<span>2. What is the magnitude Phi_final of the total magnetic flux through the coil after it is rotated? </span>
<span>3. What is the magnitude of the average emf induced in the coil?</span>
formula= W=f*d
w=work done
f=force
d=distance
w=f*d
w= 5n*0(does not budge)means does not move so distance is zero
w=5J
The work done by the children on the sumo wrestler is 5J
The car traveled 1.00363 kilometers in the 55.2s and the speed of 55m/s
Answer:
3.528×10² V.
Explanation:
potential difference: This is the work done when one coulomb of charge moves from one point to another in an electric field. The S.I unit of potential difference is volt. The formula of potential difference is given as,
V = kq/r..................... Equation 1
And
E = kq/r² .................. Equation 2
Comparing equation 1 and equation 2,
V = E×r............................. Equation 3
Where V = potential difference, E = Electric field between the plate of the capacitor, r = distance between the plate.
Given: E = 6.3×10⁵ V/m, r = 0.56 mm = 0.00056 m.
Substitute into equation 3,
V = 6.3×10⁵×0.00056
V = 3.528×10² V.
Hence the potential difference of the plate = 3.528×10² V.
