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Aneli [31]
3 years ago
15

What is the reducing agent in the reaction below?

Chemistry
1 answer:
trapecia [35]3 years ago
8 0
Al    is  the  reducing  agent.That    is  answer  B  is  the  above  answer
  Al  acts  as  a  strong  reducing  agent.  It  reduces  crO3  to  form cr  while  Al  is  oxidized  to  Al2O3.    Al is  capable  to  reduce  cr  since  Al  is  higher  in   reactivity  series  than  cr.
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2. How many grams of NaCl are required to prepare 0.40 L of a 0.75 M solution?
Yuri [45]

The mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g. Details about mass can be found below.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles of a solution must be initially calculated by using the following formula:

molarity = no of moles ÷ volume

no of moles = 0.75 × 0.40

no of moles = 0.3 moles

mass of NaCl = 0.3 × 58.5 = 17.55g

Therefore, the mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g.

Learn more about mass at: brainly.com/question/19694949

#SPJ1

4 0
2 years ago
How many moles of oxygen are there in 3 moles of Zn(NO3)2? (2 points)
muminat

there are 6 moles of oxygen in Zn(No3)2

4 0
2 years ago
Will name brainliest!!!!!
dem82 [27]

According to sources, the most probable answer to this query is the reaction is spontaneous and will proceed without any energy input. This means that energy was produced and can result to a reaction.We appreciate your questions. Please, never hesitate to ask more in Brainly your queries. 
7 0
3 years ago
Read 2 more answers
Quicklime is an incredibly caustic substance that has been used during plagues to quickly dissolve diseased corpses. Calcium car
Mazyrski [523]

Answer:I just want points

Explanation:because I need them for future questions

6 0
2 years ago
Ancient Romans built often out of bricks and mortar. A key ingredient in their mortar was quicklime (calcium oxide), which they
velikii [3]

The question has missing information. At part 1 it is "Write a balanced chemical equation, including physical state symbols, for the decomposition of solid calcium carbonate (CaCO3) into solid calcium oxide and gaseous carbon dioxide."

Part 2. "Suppose 19.0 L of carbon dioxide gas are produced by this reaction, at a temperature of 290.0°C and pressure of exactly 1 atm. Calculate the mass of calcium carbonate that must have reacted (...)"

Answer:

41.0 g

Explanation:

1. Calcium oxide has molecular formula CaO and carbon dioxide CO₂, thus, the reaction will be:

CaCO₃(s) → CaO(s) + CO₂(g)

The equation is already balanced because there's the same number of each element on both sides.

2. First, let's calculate the number of moles of CO₂ produced by the ideal gas law:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature (290°C = 273 = 563 K).

1*19 = n*0.082*563

46.166n = 19

n = 0.4116 mol

By the stoichiometry of the reaction:

1 mol of CaCO₃ ------ 1 mol of CO₂

x ----- 0.4116 mol

By a simple direct three rule:

x = 0.4116 mol of CaCO₃.

The molar mass of the calcium carbonate is 100 g/mol, thus the mass (m) is the number of moles multiplied by it:

m = 0.4116*100

m = 41.16 g = 41.0 g

4 0
3 years ago
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