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k0ka [10]
3 years ago
12

QUESTION 8

Chemistry
2 answers:
grin007 [14]3 years ago
5 0

answer to Question will be 2 electron as it forms 2H+

True [87]3 years ago
3 0

Answer :

(8) The number of electrons added to balance the reaction should be, Two electrons.

(9) The correct option is, 2I^-\rightarrow I_2+2e^- (oxidized) and 2IO_3^-+2e^-\rightarrow I_2 (reduced)

Explanation :

(8) The given oxidation half-reaction is,

H_2O_2\rightarrow 2H^++O_2

The given oxidation half-reaction is an unbalanced reaction because in this reaction the charges are not balanced. So, in order to balance the half reaction we are adding two electrons on product side of the reaction and the oxidation means loss of electrons.

Thus, the balanced oxidation half-reaction will be,

H_2O_2\rightarrow 2H^++O_2_2e^-

Hence, the number of electrons added to balance the reaction should be, Two electrons.

(9) Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given oxidation-reduction reaction is :

I^-+IO_3^-\rightarrow I_2

The oxidation-reduction half reaction will be :

Oxidation : 2I^-\rightarrow I_2+2e^-

Reduction : 2IO_3^-+2e^-\rightarrow I_2

In this reaction, the oxidation state of 'I' changes from (-1) to (0) that means 'I' lost 2 electrons and it shows oxidation and the oxidation state of 'I' changes from (+5) to (0) that means 'I' gains 2 electrons and it shows reduction.

Hence, the correct option is, 2I^-\rightarrow I_2+2e^- (oxidized) and 2IO_3^-+2e^-\rightarrow I_2 (reduced)

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LuckyWell [14K]

Answer:

The cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

Explanation:

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Time = 5 hour per day

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Fluorescent bulb power = 25 W = 0.025 KW

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6 0
3 years ago
During action potential, positively charged ________ ions move inside the cell.
Tems11 [23]

During action potential, positively charged  sodium ions move inside the cell.

So option D is correct one.

The sodium ion moves inside the cell during a action potential. The stage of action potential is called depolarization . This open voltage gated sodium channel.

Action potentials ( those electrical impulse that send signals around body )  is nothing but more than temporary shift ( from negative to positive ) in the neuron's membrane potential caused by ions suddenly flowing in and out of the neuron.

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An active potential propagates along the cell membrane of an axon until  it reaches the terminal button.

to known more about action potential

brainly.com/question/27095019

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2 years ago
A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and
Dmitry_Shevchenko [17]

Answer:

1. Rate =k [NO]^{2}[Cl_{2}]

2. k= 0.42 \frac{L^{2}}{mol^{2}*s}

Explanation:

Rate =k [NO]^{m}[Cl_{2}]^{n}

Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2

Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1

Rate =k [NO]^{2}[Cl_{2}]^{1}

Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12}  = 0.42 \frac{L^{2}}{mol^{2}*s}

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kupik [55]
  <span>C. polar bonds and asymmetrical structure 
If the molecule contains polar bonds but it has a symmetrical structure, the polar bonds will cancel each other out so the overall molecule will be non-polar. 
On the other hand, if the molecule contains polar bonds but has an asymmetrical structure, then the polar bonds won't cancel each other out, so the overall molecule ends up being polar. 
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Yuliya22 [10]

Answer:

This question appears incomplete

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