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Dafna11 [192]
2 years ago
7

Which of the following is an acid-base neutralization reaction?

Chemistry
1 answer:
algol132 years ago
3 0

Answer:

D

Explanation:

The reaction in which an acid reacts with a base to form salt and water is called acid base reaction.

here, HCL ( strong acid) reacts with KOH (strong base) and KCL (salt) and H2O (water) is formed.

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Carbon disulfide is formed by the reaction of coke (carbon) with sulfur dioxide. how many moles of cs2 will be generated if 8.0
trapecia [35]
<span>The equation that produces carbon disulfide from the reaction of coke and sufur dioxide is expressed in the balanced equation: c+ 2sO2 = CS2 + 2O2. For every mole of coke reacted, there is one mole of carbon disulfide produced. Hence the answer here is 8 moles of CS2 </span>
7 0
3 years ago
He (Helium) is _________ atomic molecule.
babunello [35]

Answer:

Monatomic molecule

Explanation:

Each helium atom has 2 electrons, which is already the maximum no. of electrons that can fit in the first electron shell. When the outermost electron shell is full (2 for the first layer, 8 for others), the atom is stable.

Helium atom itself is already stable, so it doesn't need to combine with another helium atom to form a molecule, hence we call it monatomic.

8 0
3 years ago
Read 2 more answers
Given the reaction: solid sodium reacts with chlorine gas to form solid sodium chloride How many moles of the product result fro
lyudmila [28]

Answer:

number of moles of NaCl produce = 12 mol

Explanation:

Firstly, we need to write the chemical equation of the reaction and balance it .

Na(s) + Cl2(g) → NaCl(s)

The balanced equation is as follows:

2Na(s) + Cl2(g) → 2NaCl(s)

1 mole(71 g) of chlorine produces 2 moles(117  g) of sodium chloride

6 mole of chlorine gas will produce ? mole of sodium chloride

cross multiply

number of moles of NaCl produce = 6 × 2

number of moles of NaCl produce = 12 moles

number of moles of NaCl produce = 12 mol

3 0
3 years ago
Calculate the freezing point of a solution containing 5. 0 grams of kcl and 550. 0 grams of water. the molal-freezing-point-depr
lutik1710 [3]

The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Using the equation,

ΔT_{f} = iK_{f}m

where:

ΔT_{f} = change in freezing point (unknown)

i = Van't Hoff factor

K_{f} = freezing point depression constant

m = molal concentration of the solution

Molality is expressed as the number of moles of the solute per kilogram of the solvent.

Molal concentration is as follows;

MM KCl = 74.55 g/mol

molal concentration = \frac{5.0g*\frac{1mol}{74.55g} }{550.0g*\frac{1kg}{1000g} }

molal concentration = 0.1219m

Now, putting in the values to the equtaion ΔT_{f} = iK_{f}m we get,

ΔT_{f} = 2 × 1.86 × 0.1219

ΔT_{f} = 0.4536°C

So, ΔT_{f} of solution is,

ΔT_{f_{solution} } = 0.00°C - 0.45°C

ΔT_{f_{solution} } =  - 0.45°C

Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Learn more about freezing point here;

brainly.com/question/3121416

#SPJ4

7 0
1 year ago
Identify the control group the experimental group the independent variable and the dependent variable
denis-greek [22]
Control group: 50 dogs continuing their normal diet
Experiments group: 50 dogs chosen to eat the new food
Independent variable: dog food
Dependent variable: the dogs’ weight
3 0
3 years ago
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