Have about 5 beakers all with different temperatures of water. Put in a teaspoon of salt at a time and when it stops dissolving stop adding and record how much salt it took. It should be more salt as the temperature rises. The independent variable is the waters temperature. The dependent variable is how much salt is used. Make sure that there is the same amount of water in each beaker. Or else it won’t work.
Answer:
<em>To calculate the average atomic mass, multiply the fraction by the mass number for each isotope, then add them together.</em>
<em>hope this helps</em><em> </em><em><</em><em>3</em>
Answer:
239.15. OR round down 239
Explanation:
Answer: The specific heat capacity of chromium is 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of chromium = 15.5 g
= mass of water = 55.5 g
= final temperature =
= temperature of chromium = 
= temperature of water = 
= specific heat of chromium= ?
= specific heat of water= 
Now put all the given values in equation (1), we get
![-15.5\times c_1\times (19.5-18.9)=[55.5\times 4.184\times (19.5-100)]](https://tex.z-dn.net/?f=-15.5%5Ctimes%20c_1%5Ctimes%20%2819.5-18.9%29%3D%5B55.5%5Ctimes%204.184%5Ctimes%20%2819.5-100%29%5D)
The specific heat capacity of chromium is
