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Westkost [7]
3 years ago
14

Suppose you were asked to demonstrate electromagnetic induction. Which of the following situations will result in an electric cu

rrent?
A magnet is moving toward a wire loop.
A wire loop is moving away from a magnet.
A wire loop is rotated near a magnet.
All of the above
Physics
1 answer:
Serggg [28]3 years ago
6 0
The correct answer is "All of the above".

In fact, electromagnetic induction occurs when there is a change of the magnetic flux through the area enclosed by a circuit (in this case, the area enclosed by the wire loop).
The magnetic flux \Phi_B through a certain surface is given by
\Phi_B=B A cos \theta (1)
Where B is the intensity of the magnetic field, A is the area enclosed by the circuit and \theta is the angle between the direction of the field B and the perpendicular to the area.

In the first situation, the magnet is getting closer to the loop, so the magnetic flux through the area enclosed by the wire is increasing (because the intensity of the magnetic field B is increasing). Situation 2) is the opposite case: the wire loop is moving away from the magnet, so the intensity of the magnetic field B is decreasing, and therefore the magnetic flux is decreasing as well.
Finally, in the third situation the wire loop is rotating. Here the distance between the loop and the magnet is not changing, but remember that the magnetic flux depends also on the angle between the direction of the magnetic field and the perpendicular (formula 1), and so since the wire loop is rotating, than this angle is changing, therefore the magnetic flux is changing as well.
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Which temperature scale has no negative temperatures A. Celsius B. Joule C. Fahrenheit D. Kelvin
Brilliant_brown [7]
The Kelvin scale has no negatives on it.

Zero Kelvin is 'Absolute Zero', and nothing can get colder than that.
6 0
3 years ago
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A 50 N girl climbs the flight of stairs in 3 seconds. How much work does she
kvv77 [185]
She uses 0 power because she simply has no gas left. She used all of it getting a 50 pc McDonald’s nugget with a side of ranch and a medium fry and a large water.
7 0
3 years ago
An archer puts a 0.30-kg arrow to the bowstring. An average force of 201 N is exerted to draw the string back 1.3 m. Assuming th
vovikov84 [41]

Answer:

41.74 m/s

Explanation:

The energy used to draw the bowstring = the kinetic energy of the arrow.

Fd = 1/2mv²................................ Equation 1

Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.

make v the subject of the equation

v = √(2Fd/m)...................... Equation 2

Given: F = 201 N, m = 0.3 kg, d = 1.3 m.

Substitute into equation 2

v = √(2×201×1.3/0.3)

v = √(1742)

v = 41.74 m/s.

Hence the arrow leave the bow with a speed of 41.74 m/s

3 0
3 years ago
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A space probe is fired as a projectile from the Earth's surface with an initial speed of 2.05 104 m/s. What will its speed be wh
Elanso [62]

Answer:

The value is  v  =  2.3359 *10^{4} \ m/s

Explanation:

From the question we are told that

  The  initial speed is u =  2.05 *10^{4} \  m/s

 Generally the total energy possessed by the space probe when on earth is mathematically represented as

             T__{E}} =  KE__{i}} +  KE__{e}}

Here  KE_i is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

          KE_i =   \frac{1}{2}  *  m  *  u^2

=>       KE_i =   \frac{1}{2}  *  m  *  (2.05 *10^{4})^2

=>       KE_i =  2.101 *10^{8} \ \ m \ \ J

And  KE_e is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

       KE_e =  \frac{1}{2}  *  m *  v_e^2

Here v_e is the escape velocity from earth which has a value v_e =  11.2 *10^{3} \  m/s

=>    KE_e =  \frac{1}{2}  *  m *  (11.3 *10^{3})^2

=>    KE_e =  6.272 *10^{7} \  \  m  \ \   J

Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

        KE_p =  \frac{1}{2}  *  m *  v^2

Generally from the law energy conservation we have that

        T__{E}} =  KE_p

So

       2.101 *10^{8}  m  +  6.272 *10^{7}  m  =   \frac{1}{2}  *  m *  v^2

=>     5.4564 *10^{8} =   v^2

=>     v =  \sqrt{5.4564 *10^{8}}

=>     v  =  2.3359 *10^{4} \ m/s

4 0
3 years ago
The Earth and the Moon are attracted to each other by universal gravitation. The Earth is much more massive than is the Moon. Do
OverLord2011 [107]

Answer:

Earth attract the Moon with a force that is greater.

Explanation:

According to the law of gravitation, the gravitational force between two masses is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Mathematically, F1 = Gm1m2/r²... 1

Let m1 be the mass of the earth and m2 be that of the moon

If the Earth is much more massive than is the Moon, the new force of attraction between them will become;

F2= G(2m1)m2/r²

F2 = 2Gm1m2/r² ... (2)

Dividing eqn 1 by 2 we have;

F1/F2 = (Gm1m2/r²)÷(2Gm1m2/r²)

F1/F2 = Gm1m2/r²×r²/2Gm1m2

F1/F2 = 1/2

F2=2F1

This shows that that the earth will attract the moon by a force 2times the initial force of the masses(i.e a much greater force)

6 0
3 years ago
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