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koban [17]
3 years ago
15

When the Earth is positioned between the Moon and the Sun the following are possible:

Physics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

lunar eclipse

Explanation:

if the earth is between to two (not bringing the moons orbit into account) a lunar eclipse happens

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See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in
Rasek [7]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

1. According to person standing on ground ~

  • The person is in motion

2. According to The car ~

  • The person is not in motion

3. According to the Seat ~

  • The person is not in motion

4. According to another person on ride ~

  • The person is not in motion

5. According to the track ~

  • The person is in motion

6. According to the Sun ~

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I hope that's what you were looking for, goodluck for your assignment ~

7 0
2 years ago
What is cell in electricity?
agasfer [191]

Answer:

An electrical cell is a device used to generate electricity, or to make chemical reactions by applying electricity.

7 0
4 years ago
What is the wavelength of a radar signal that has a frequency of 27 GHz? The speed of light is 3 × 108 m/s. Answer in units of m
marusya05 [52]

Explanation:

speed of light= c

wave length= L

frequency= f

c=Lf → L= c/f → L= 3 × 10⁸/ 27 × 10⁹ → L = 1/90 ≈ 0.011 m

4 0
2 years ago
The clouds in the sky appear to be white because the clouds _____?
scZoUnD [109]
D. White is a reflectiom of all colors
3 0
3 years ago
Radar uses radio waves of a wavelength of 2.4 \({\rm m}\) . The time interval for one radiation pulse is 100 times larger than t
blondinia [14]

Answer:

120 m

Explanation:

Given:

wavelength 'λ' = 2.4m

pulse width 'τ'= 100T ('T' is the time of one oscillation)

The below inequality express the range of distances to an object that radar can detect

τc/2 < x < Tc/2 ---->eq(1)

Where, τc/2 is the shortest distance

First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'

f = c/λ (c= speed of light i.e 3 x 10^{8} m/s)

f= 3 x 10^{8} / 2.4

f=1.25 x  10^{8} hz.

As, T= 1/f

time of one oscillation T= 1/1.25 x  10^{8}

T= 8 x 10^{-9} s

It was given that pulse width 'τ'= 100T

τ= 100 x 8 x 10^{-9} => 800 x 10^{-9} s

From eq(1), we can conclude that the shortest distance to an object that this radar can detect:

x_{min}= τc/2 =>  (800 x 10^{-9} x 3 x 10^{8})/2

x_{min}=120m

8 0
3 years ago
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