Answer:5101.35v
Explanation:
Radius of gold nucleus=7.3×10-15m and a charge of +79e
Q= 79e
e=1.6×10^-19
q= +2e
The nucleus is considered as the point charge where the potential energy between the charges are
U = 1/(4×3.142×Eo)×(qQ)/r
Where r is distance between the charges and the nucleus
r=R+d
V=U/q
U= 1/(4×3.142×Eo)×Q/r
V= 1/(4×3.142×Eo)×Q/(r+d)
9.0×10^9 ×(79×10^-19)/(7.3×10^-15)+(1.5×10^-14)
V= 9.0×10^9 ×(1.264×10^-17)/(2.23×10^-14)
V= 9×10^9×(5.67×10^-14)= 5101.35v
Answer:
<h2>121ohms</h2>
Explanation:
Formula used for calculating power P = current * voltage
P = IV
From ohms law, V = IR where R is the resistance. Substituting V = IR into the formula for calculating power, we will have;
P = IV
P =(V/R)V
P = V²/R
Given parameters
Power rating of the bulb P = 100 Watts
Source voltage V = 110V
Required
Resistance of the bulb R
Substituting the given parameters into the formula for calculating power to get Resistance R;
P = V²/R
100 = 110²/R
R = 110²/100
R = 110 * 110/100
R = 12100/100
R = 121 ohms
<em>Hence, the resistance of this bulb is 121 ohms</em>
For the second question you’re solving for resistance. resistance= voltage/ current. 120/0.5= 240. the answer is 240 ohms
for the third question you would do 2*4 since it’s asking for voltage, the answer is 8 volts :)
Answer:
The value is 
Explanation:
From the question we are told that
The initial speed is 
Generally the total energy possessed by the space probe when on earth is mathematically represented as

Here
is the kinetic energy of the space probe due to its initial speed which is mathematically represented as
=>
=> 
And
is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

Here
is the escape velocity from earth which has a value 
=> 
=> 
Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

Generally from the law energy conservation we have that
So

=> 
=> 
=> 
Answer:
2.63 cm
Explanation:
Hooke's law gives that the force F is equal to cy where c is spring constant and x is extension
Making c the subject of the formula then

Since F is gm but taking the given mass to be F

By substitution now considering F to be 3.3 kg
