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nekit [7.7K]
3 years ago
8

A weightlifter liftsa 1,250-N barbell 2 m in 3 s. how much power was used to lift the barbell?

Physics
1 answer:
STatiana [176]3 years ago
5 0
Power = Force * Distance/ time
P = 1,250 * 2/3
P = 2,500/3
P = 833.33 Watts

So, your final answer is 833.33 Watts
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frictonal force due to the surface of irregularities

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Two objects of the same mass, but made of different materials, are initially at the same temperature. Equal amounts of heat are
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Answer:

The final temperature of the two objects is the same.

Explanation:

The expression for the heat energy in terms of mass, specific heat and the change in the temperature is as follows:

Q=mc(T_{f} -T_{i})

Here, Q is the heat energy, m is the mass of the object, c is the specific heat and T_{f},T_{i} are the final temperature and initial temperature.

According to the given question, Two objects of the same mass, but made of different materials, are initially at the same temperature. Equal amounts of heat are added to each object.

Q=mc(T_{f}-T_{i})                                             ............(1)

Q=mc(T'_{f}-T_{i})                                            .............(2)

From (1) and (2),

mc(T_{f}-T_{i})=mc(T'_{f}-T_{i})

T_{f}-T_{i}=T'_{f}-T_{i}

T_{f}=T'_{f}

Therefore, the final temperature of the two objects is the same.

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Consider a ball (with moment of inertia I=2/5MR^2) which bounces elastically
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Read 2 more answers
A transverse sinusoidal wave is moving along a string in the positive direction of an x axis with a speed of 89 m/s. At t = 0, t
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Answer:

The answer is below

Explanation:

Given that:

y = transverse displacement = 4.2 cm = 0.042 m at x = 0 and t = 0.

Speed = v = 89 m/s, maximum transverse speed of the string particle = u_m = 16 m/s.

ω = u_m / y_m = 16 / 0.42 = 380.95 rad/s

a) Frequency = ω/2π = 380.95 / 2π = 60.63 Hz

b) Wavelength (λ) = speed / frequency

λ = v / f = 89/63.66= 1.468 m

c) Using the wave equation:

y=y_msin(kx \pm wt \pm \phi)\\y=0.042,t=0,x=0\\\\Hence\\y_m=0.042\ m

d) Wave number k is given by:

k = 2π / λ = 2π / 1.468 = 4.28 rad/s

e) The angular velocity is given by:

ω = u_m / y_m = 16 / 0.42 = 380.95 rad/s

f)  Using the wave equation:

y=y_msin(kx \pm wt \pm \phi)\\\\y=0.042,t=0,x=0,y_m=0.042\\\\Hence\\0.042=0.042sin(4.28(0)\pm 380.95(0)\pm \phi)\\\\sin\phi=1\\\\\phi=\frac{\pi}{2} \\\\y=0.042sin(4.28x\pm 380.95t\pm \frac{\pi}{2})

g) Since the wave is in the positive x direction, hence ω is negative

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3 years ago
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