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Akimi4 [234]
3 years ago
12

How does an NASCAR works?

Physics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

It works by adding an engine, a transmission, car batteries, an extra strong frame in case of a crash, and much more needed things. When it races, The rubber often burns a lot, because of the high speeds that it goes, so that is why they so often change the tires. They give it a full tank of gas, which is basically like the car's idea of food and water. A NASCAR must have a trong engine to go so fast in order to win a race.

Explanation:

Just think of it like building a lego car just hot gluing the legos together and seeing if it breaks.

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An object with charge q=−6.00×10−9C is placed in a region of uniform electric field and is released from rest at point A. After
shtirl [24]

Answer:

its a

Explanation:

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3 years ago
A 0.15-kg ball is thrown into the air and rises to a height of 20.0 m. How much kinetic energy did the ball initially have?
zzz [600]
IF the toss was straight upward, then the kinetic energy it got
from the toss is the gravitational potential energy it has at the top,
where it stops rising and starts falling.

Potential energy =  (mass)  x   (gravity) x (height)

                           = (0.15 kg) x (9.8 m/s²) x (20 m)

                           =      29.4 kg-m²/s²  =  29.4 joules .
7 0
3 years ago
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An astronomer studies an image taken by a satellite in space and sees an area of gas, dust, and many stars distributed along spi
DanielleElmas [232]

Answer:the answer is galaxy

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3 years ago
An airplane flying at an altitude of 6 miles passes directly over a radar antenna. When the airplane is 10 miles away (s = 10),
Novosadov [1.4K]

Answer:

Explanation:

Given

altitude of the Plane h=6\ miles

When Airplane is s=10\ miles away

Distance is changing at the rate of \frac{\mathrm{d} s}{\mathrm{d} t}=290\ mph

From diagram we can write as

h^2+x^2=s^2

differentiate above equation w.r.t time

2h\frac{\mathrm{d} h}{\mathrm{d} t}+2x\frac{\mathrm{d} x}{\mathrm{d} t}=2s\frac{\mathrm{d} s}{\mathrm{d} t}

as altitude is not changing therefore \frac{\mathrm{d} h}{\mathrm{d} t}=0

0+x\frac{\mathrm{d} x}{\mathrm{d} t}=s\frac{\mathrm{d} s}{\mathrm{d} t}

at s=10\ miles\ and\ h=6\ miles

substitute the value we get x=\sqrt{10^2-6^2}=8\ miles

8\times \frac{\mathrm{d} x}{\mathrm{d} t}=10\times 290

\frac{\mathrm{d} x}{\mathrm{d} t}=362.5\ mph

5 0
3 years ago
A point charge q1 is held stationary at the origin. A second charge q2 is placed at point a, and the electric potential energy o
likoan [24]

Answer:

U_{b}=+7.3*10^{-8}J

Explanation:

Given data

Electric potential at point a is Ua=5.4×10⁻⁸J

q₂ moves to point b where a negative work done on it  W_{a-b}=-1.9*10^{-8}J

Required

Electric potential energy Ub

Solution

When a particle moves from a point where the potential is Ua to a point where it is Ub the change in potential energy is equal to work done where the force exerted on the charge is conservative and work done is given by:

W_{a-b}=U_{a}-U_{b}\\U_{b}=U_{a}-W_{a-b}

Now  substitute the given values

So

U_{b}=5.4*10^{-8}J-(-1.9*10^{-8}J)\\U_{b}=+7.3*10^{-8}J

3 0
3 years ago
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