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aleksley [76]
3 years ago
10

the sum of three numbers is 44. the first number is 1 subtracted from 4 times the second number. the third is 9 more than the se

cond number. find each number
Mathematics
1 answer:
ch4aika [34]3 years ago
7 0
Second # is X
First # is 4X - 1
Third # is X + 9

x + (4x-1) + (x+9) =44
6x+8=44
6x+8-8=44-8
6x=36
6x/6=36/6
x=6  answer
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see the attached figure to better understand the problem

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