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3 years ago

10

the sum of three numbers is 44. the first number is 1 subtracted from 4 times the second number. the third is 9 more than the se

cond number. find each number

1 answer:

ch4aika [34]3 years ago

7 0

Second # is X
First # is 4X - 1
Third # is X + 9

x + (4x-1) + (x+9) =44
6x+8=44
6x+8-8=44-8
6x=36
6x/6=36/6
x=6 answer

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<h3>How to simplify the expression?</h3>

The expression is given as:

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Cancel out the common factors

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Take the LCM

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