the sum of three numbers is 44. the first number is 1 subtracted from 4 times the second number. the third is 9 more than the se
cond number. find each number
1 answer:
Second # is X
First # is 4X - 1
Third # is X + 9
x + (4x-1) + (x+9) =44
6x+8=44
6x+8-8=44-8
6x=36
6x/6=36/6
x=6 answer
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