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guapka [62]
3 years ago
13

List 5 of the 8 characteristics that define something as living

Chemistry
1 answer:
WARRIOR [948]3 years ago
7 0
<span>Made of cells
</span><span>Reproduce
</span><span>Grow and Develop
</span><span>Respond to their Environment
</span><span>Genetic code</span>
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Wavelengths are often represented in nm. What is the diameter of a helium (He) atom in
lianna [129]

Answer:

Diameter He = 0,1 nm.

Explanation:

Km to nm:

⇒ Diameter He = 1.0 E-13 Km * ( 1000 m / Km ) * (  1 E9 nm / m )

⇒ Diameter He = 0.1 nm

5 0
3 years ago
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What is the PH of a solution if [H3O]= 1.7×10-3 M
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14 Molar is its molarity.
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Material A has a small latent heat of fusion. Material B has a large heat of fusion. Which of the following statements is true?
Olin [163]
The correct answer would be the first option. Material A having a smaller latent heat of fusion would mean that it will take only less energy to phase change into the liquid phase. Latent of heat of fusion is the amount of energy needed of a substance to phase change from solid to liquid or liquid to solid.
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With which group would group 18 most likely bond
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The noble gases (Group 18) are located in the right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactivE

Explanation:

8 0
3 years ago
2
son4ous [18]

Answer: The molar enthalpy change is 73.04 kJ/mol

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

moles of HCl= molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol

As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.

volume of water = 100.0 ml + 50.0 ml = 150.0 ml

density of water = 1.0 g/ml

mass of water = volume \times density=150.0ml\times 1.0g/ml=150.0g

q=m\times c\times \Delta T

q = heat released

m = mass  = 150.0 g

c = specific heat = 4.184J/g^0C

\Delta T = change in temperature = 4.83^0C

q=150.0\times 4.184\times 4.83

q=3031.3J

Thus 0.0415 mol of HCl produces heat = 3031.3 J

1 mol of HCL produces heat = \frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ

Thus molar enthalpy change is 73.04 kJ/mol

8 0
3 years ago
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