Multiply .800 moles of O2 by Avagadro's number divided by 1 mole. This will get rid of the moles on the bottom and leave you with molecules. So technically .800 times 6.02x10^23.
Answer:
H2Br + 2KOH ----- K2Br + 2H2O
Balance Chemical Equation is as follow,
<span> Cu + 2 AgNO</span>₃ → 2 Ag + Cu(NO₃)₂
According to Balance Equation,
2 Moles of Ag is produced by reacting = 1 Mole of Cu
So,
0.854 Moles of Ag will be produced by reacting = X Moles of Cu
Solving for X,
X = (0.854 mol × 1 mol) ÷ 2 mol
X = 0.427 Moles of Cu
Result:
0.854 Moles of Ag are produced by reacting 0.427 Moles of Cu.
Answer:
D. The rate decreases as reactants are used up.
Explanation:
Initially, the rate increases until the reaction is at equilibrium. At equilibrium, the rate is constant.
As the reaction progresses, the rate decreases to zero when reactants are used up ( for irriversible reactions only )
