a sound wave has a frequency of 1192 hertz. all sound waves in air travel at 322m/s. find the wave length of the sound wave
1 answer:
Answer:
0.167 m
Explanation:
By the definition of the velocity if a wave ,
The velocity of light, v, is the product of its wavelength, λ , and its frequency, f.
V= fλ
frequency - number of occurrences in a unit time
Wavelength - distance between corresponding points of two consecutive waves
(check the graph for wavelength)
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Answer:
(a) 0.17 m
(b) 5.003 m
(c) 6.38 × N
(d) 7.37 × N
Explanation:
(a) The minimum value of will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the <em>minimum value of x= 0.17 m</em>.
(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.
<em>Hence, the maximum distance is 5.002 m</em>
(c) For minimum magnitude we use the minimum distance calculated in (a)
Minimum Distance = 0.17 m
For electrostatic force=
×
(d) For maximum magnitude, we use the maximum distance calculated in (b)
Maximum Distance = 5.002 m
Using the formula for electrostatic force again:
F =
F= 7.37× N