Local Area Network (LAN) ...
Wireless Local Area Network (WLAN) ...
Campus Area Network (CAN) ...
Metropolitan Area Network (MAN) ...
Wide Area Network (WAN) ...
Storage-Area Network (SAN) ...
System-Area Network (also known as SAN)
Answer:
d. from the equilibrium position to the bottom and then back to the equilibrium.
g. from the top position to the bottom and then back to the top.
h. from the bottom position to the top and then back to the bottom.
Explanation:
It is the case of SHM or Simple Harmonic Motion. Firstly, there is a need to understand the time interval or time period. The standard definition of time period in simple harmonic motion is
"the time period required for the system to complete its one cycle"
Now one have to consider that the system given above, the motion of mass attached to spring will follow the path of motion from equilibrium point to bottom to equilibrium point to top, then equilibrium point to the bottom and so on.
to choose right answer you must have to consider the option, in which the starting point and ending point of the mass is same. If mass starts from top, the time it will take to reach on top again, will be defined as its time period and so in the case of bottom or equilibrium as starting point. Hence, "d", "g" and "h" are right answers.
mercury is the closest planet from the sun
The kinetic energy will rise once the body comes back down. As it goes up, the potential energy increases while the kinetic energy decreases. Once the body is at its maximum height, the potential energy is at it’s highest. When it starts falling, it will gain kinetic energy and lose potential energy.
The cells are called insibatss, I think I spelled that right but
