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MrRa [10]
3 years ago
10

A basketball player throws a ball at 60° to the horizontal at a net 4.0m away. The height of the net is 3.3m. The ball leaves hi

s hands at a height 2.0m from the ground. What is the initial speed of the ball?
Th pic above is my ans, but it's quite wierd. So if it's wrong, what is the correct ans, and why my ans is wrong(what mistakes i did). Thanks

Physics
1 answer:
Hoochie [10]3 years ago
4 0
Excellent work!
Your calculations are correct, but near the end, you have forgotten to cancel u.  If you cancel the u, the linear term becomes a constant, and the resultant equation becomes a simple quadratic which is much easier to solve.
I get u=7.468 m/s using g=9.81 (as you did)
You will rework and should get 7.468 m/s as well.

Congrats for the good work!

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Answer:

20 [N], in the opposite direction of the first force.

Explanation:

We know that newton's second law stipulates that the sum of forces on a body must be equal to the product of mass by acceleration.

SumF = m*a\\30 + F = 2*5\\F = 30 - (2*5)\\F = - 20 [N]

The negative sign means that the other force acting on the body must be in the opposite direction to the force of 30 [N]

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In a region of space where gravitational forces can be neglected, a sphere is accelerated by a uniform light beam of intensity 8
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Answer:

The correct answer is B

Explanation:

To calculate the acceleration we must use Newton's second law

      F = m a

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To calculate the force we use the defined pressure and the radiation pressure for an absorbent surface

       P = I / c        absorbent surface

       P = F / A

       F / A = I / c

       F = I A / c

The area of ​​area of ​​a circle is

      A = π r²

We replace

     F = I π r² / c

Let's calculate

     F = 8.0 10⁻³ π (1.0 10⁻⁶)²/3 10⁸

     F = 8.375 10⁻²³ N

Density is

      ρ = m / V

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      m = 4500 (4/3 π (1 10⁻⁶)³)

      m = 1,885 10⁻¹⁴ kg

Let's calculate the acceleration

     a = 8.375 10⁻²³ / 1.885 10⁻¹⁴

     a = 4.44 10⁻⁹ m/s²               absorbent surface

The correct answer is B

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