A basketball player throws a ball at 60° to the horizontal at a net 4.0m away. The height of the net is 3.3m. The ball leaves hi
s hands at a height 2.0m from the ground. What is the initial speed of the ball?
Th pic above is my ans, but it's quite wierd. So if it's wrong, what is the correct ans, and why my ans is wrong(what mistakes i did). Thanks
Th pic above is my ans, but it's quite wierd. So if it's wrong, what is the correct ans, and why my ans is wrong(what mistakes i did). Thanks
1 answer:
Excellent work!
Your calculations are correct, but near the end, you have forgotten to cancel u. If you cancel the u, the linear term becomes a constant, and the resultant equation becomes a simple quadratic which is much easier to solve.
I get u=7.468 m/s using g=9.81 (as you did)
You will rework and should get 7.468 m/s as well.
Congrats for the good work!
Your calculations are correct, but near the end, you have forgotten to cancel u. If you cancel the u, the linear term becomes a constant, and the resultant equation becomes a simple quadratic which is much easier to solve.
I get u=7.468 m/s using g=9.81 (as you did)
You will rework and should get 7.468 m/s as well.
Congrats for the good work!
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Answer:
The truck's speed is 4.04 m/s.
Explanation:
Given that,
Emit frequency = 600 Hz
Beat = 7.00 beat/sec
We need to calculate the truck's speed
Using formula of speed
Where, v = speed of sound
Put the value into the formula
Hence, The truck's speed is 4.04 m/s.
Answer:
The distance between the ships is 87.84 km.
Explanation:
Given that,
Angle of first ship= 40°
Speed of first ship = 18 knots
Angle of second ship= 130°
Speed of second ship = 26 knots
We need to calculate the resultant velocity
Using cosine rule
Put the value into the formula
We need to calculate the distance between the ships
Put the value into the formula
Hence, The distance between the ships is 87.84 km.
