Question

What volume of 0.10 M NaOH is required to neutralize 30 mL of 0.10 M HCl?

Answer 1

30 mL. The two compounds need to balance each other out.

Answer 2

Answer : The volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.

Solution :

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of NaOH solution = 0.10 M

$V_1$ = volume of NaOH solution = ?

$M_2$ = molarity of HCl solution = 0.10 M

$V_2$ = volume of HCl solution = 30 ml

Now put all the given values in the above law, we get the volume of NaOH solution.

$(0.10M)\times V_1=(0.10M)\times (30ml)$

$V_1=30ml$

Therefore, the volume of 0.10 M NaOH required to neutralize 30 ml of 0.10 M HCl is, 30 ml.