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iragen [17]
3 years ago
12

What is the number of Cl atoms in a 784 gram pure sample of NC13?

Chemistry
1 answer:
LuckyWell [14K]3 years ago
5 0

Answer:

idk

Explanation:

idk cool pee bee mee nee hee gee fee kee

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What is the formula of acceleration?​
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The formula of acceleration is final velocity-initial velocity÷time taken

Explanation:

v-u/t

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Atoms of the element beryllium would most likely behave similar to the way _______ behaves.
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It's b. calcium 
because the outer electron structure in all of that element is similar, they have the same chemical and physical properties.<span />
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Convert 5° C into Fahrenheit.
Lady_Fox [76]

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5 in celcius is 41 in fahrenheit!

Explanation:

7 0
3 years ago
Al agregar 150g de una sustancia X en un recipiente que sostiene que contiene agua hasta 50, el nivel del agua aumenta hasta 120
vovangra [49]

Answer:

2,14 g / ml

Explanation:

Sabemos que el volumen de una sustancia es igual al cambio de volumen del agua cuando el objeto en cuestión se sumerge en el agua.

Dado que el volumen original del agua = 50 ml

Volumen de agua después de sumergir el objeto = 120 ml

Masa del objeto = 150 g

Ahora,

Densidad = masa / volumen

Densidad = 150g / 120-50 ml

Densidad = 150/70 ml

Densidad = 2,14 g / ml

4 0
2 years ago
Use the following half-reactions to write three spontaneous reactions, calculate E°cell for each reaction, and rank the oxidizin
Ainat [17]

Answer:

See explaination

Explanation:

1)

we know that

half cell with higher reduction potential is cathode

so

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

anode :

Cr(s) ---> Cr+3 + 3e-

so

overall reaction is

3 N20 + 6H+ + 2 Cr ---> 3N2 + 3H20 + 2Cr+3

now

Eo cell = Eo cathode - Eo anode

so

EO cell = 1.77 + 0.74

Eo cell = 2.51 V

now

in this case

oxidizing agents are N20 and Cr+3

reducing agents are Cr and N2

higher the reduction potential , stronger the oxidizing agent

lower the reduction potential , stronger the reducing agent

so

oxidzing agents

N20 > Cr+3

reducing agents

Cr > N2

2)

cathode :

Au+ + e- --> Au

anode :

Cr ---> Cr+3 + 3e-

overall reaction

3Au+ + Cr ---> 3Au + Cr+3

Eo cell = 1.69 + 0.74

Eo cell = 2.43

now

oxidizing agents :

Au+ > Cr+3

reducing agents :

Cr > Au

3)

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

andoe :

Au ---> Au+ + e-

overall

2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20

Eo cell = 1.77 - 1.69

Eo cell = 0.08

oxidizing agents

N20 > Au+

reducing agents

Au > N2

8 0
3 years ago
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