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Ipatiy [6.2K]
3 years ago
15

What law of motion does this picture represent

Chemistry
1 answer:
alukav5142 [94]3 years ago
7 0

Answer: none

Explanation: there is no picture attached

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How many bromine atoms are present in 39.0 g of ch2br2?
Mandarinka [93]
Answer is: there is  2,69·10²³ atoms of bromine.
m(CH₂Br₂) = 39,0 g.
n(CH₂Br₂) = m(CH₂Br₂) ÷ M(CH₂Br₂).
n(CH₂Br₂) = 39 g ÷ 173,83 g/mol.
n(CH₂Br₂) = 0,224 mol.
In one molecule of CH₂Br₂, there is two bromine atoms, so:
n(CH₂Br₂) : n(Br) = 1 : 2.
n(Br) = 0,448 mol.
N(Br) = n(Br) · Na.
N(Br) = 0,448 mol · 6,022·10²³ 1/mol.
n(Br) = 2,69·10²³.
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Elanso [62]
[Ar] 4s²
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Sulfur is the next element in the group, and it reacts with hydrogen gas (H2) in a manner similar to oxygen.

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