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Ymorist [56]
3 years ago
8

Describe some ways you could keep ice from melting over a long period of time?

Chemistry
1 answer:
olga2289 [7]3 years ago
4 0
<span>Use a light colored container
</span><span>Line the cooler or bucket with aluminum foil
</span><span>Wrap the ice bucket in a towel</span>
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HELP
Natalka [10]

Explanation:

To find the amount of product that would be formed from two or more reactants, we need to follow the following steps;

  • Find the number of moles of the given reactants.
  • Then proceed to determine the limiting reactant. The limiting reactant is the one in short supply which determines the extent of the reaction.
  • Use the number of moles of the limiting reactant to find the number of moles of the product.
  • Then use this number of moles to find the mass of the product

Useful expression:

    Mass   =  number of moles x molar mass

3 0
3 years ago
What is the specific heat of copper when heated to 221.32
Dafna1 [17]

Answer:

The specific heat of copper when heated to 221.32 (not listed form of heat measurement) is 221.32 (not listed form of heat measurement).

Explanation:

uh not really sure what else there is here, I may be missing something

5 0
2 years ago
Three chemical reactions of ethane?
Otrada [13]

Answer:

1.Hydrogenation of Alkenes and akynes.

2.Reaction of alkylhalides.

3. Halogenation.

6 0
3 years ago
if 2.0 g of hydrogen sulfide, H2S(g) reacts with 5.0 g of sodium hydroxide what mass of the excess reactant is present when the
Ronch [10]

Answer: iits 9.g

Explanation:

7 0
3 years ago
In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
zloy xaker [14]

Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

3 0
3 years ago
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