Answer:
The most common position for an double bond in an unsaturated fatty acid is delta 9 (Δ⁹)
Explanation:
Unsaturated fatty acids are carboxylic acids which contains one or more double bonds. The chain length as well as the number of double bonds is written separated by a colon. The positions of the double bonds are specified starting from the carboxyl carbon, numbered as 1, by superscript numbers following a delta (Δ). For example, an 18-carbon fatty acid containing a single double bond between carbon number 9 and 10 is written as 18:1(Δ⁹).
In most monounsaturated fatty acids, the double bond is between C-9 and C-10 (Δ⁹), and the other double bonds of polyunsaturated fatty acids are generally Δ¹² and Δ¹⁵. This positioning is due to the nature of the biosynthesis of fatty acids. In the mammalian hepatocytes, double bonds are introduced easily into fatty acids at the Δ⁹ position, but cannot introduce additional double bonds between C-10 and the methyl-terminal end. However, plants are able to introduce these additional double bonds at the Δ¹² and Δ¹⁵ positions.
MgBr2: It's formed of Magnesium Mg, and dibromide Br2. And since Magnesium is a metal and Dibromide a no-metal, it's more appropriate while naming the substance to remove the "di" from "dibromide". Following the rules for naming compounds, the prefixes "mono", "di", etc... should only be used between 2 nonmetals.
So, the name for MgBr2 is Magnesium Bromide.
Hope this Helps! :)
Hello,
Your brainliest answer would be:
1A. Both involve ion movements
1B. Passive transport moves ions from high concentration to low, using no metabolic energy.
2A. Both passive transport processes.
2B. Diffusion refers to the movement of any chemical from one place to another, whereas osmosis exclusively from one place to another.
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Hope this helps!
Answer:
C. It decreases by a factor of 4
Explanation:
F1 = kq1*q2/r²
F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4) = F1/4
Answer:
0 kgm/s
Explanation:
The momentum of Bob while resting at the river is 0 kgm/s.
This is because the momentum of any object at rest is 0.
Momentum is the quantity of motion a body contains. It is mathematically expressed as;
Momentum = m x v
m is the mass
v is the velocity
So at rest, the velocity of a body is 0m/s and therefore, the momentum is O
