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kakasveta [241]
3 years ago
12

1. What is the molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution.

Chemistry
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

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Sitting at a four-legged table there is: 1 grandma, 2 moms, 2 daughters and a granddaughter. How many legs are under the table?
lbvjy [14]

Answer:

The answer is 14 "legs"

Explanation:

There are 2 legs per person so 10 legs (5 people * 2) plus the 4 legs the table has.

3 0
3 years ago
What is one benefit and one limitation of comparative investigations
Ivan
<span>1. Seeing broader picture: determining gray areas, overlaps, and exclusions, biases, the primary focus.

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5 0
3 years ago
An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in t
dmitriy555 [2]

Answer:

P₂ = 2.7 atm

Explanation:

Given data:

Initial temperature = 30°C

Initial pressure = 3.00 atm

Final temperature = -5°C

Final pressure = ?

Solution:

Initial temperature = 30°C = 30 + 273 = 303 K

Final temperature = -5°C = -5 + 273 = 268 K

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

3.0 atm / 303 K = P₂/268 K

P₂ = 3.0 atm × 268 K / 303 K

P₂ = 804 atm. K /293 K

P₂ = 2.7 atm

7 0
3 years ago
The Ksp for BaCO3 is 5.1x10^-9. how many grams of BaCO3 will dissolve in 1000ml of water
Amanda [17]

Answer:

= 0.014 g of BaCO3

Explanation:

Let x = mol/L of BaCO3 that dissolve.  

This will give;

x mol/L Ba2+ and x mol/L CO32-  

But;

Ksp = 5.1x10^-9.

Therefore;

Ksp = 5.1 x 10^-9 = (x)(x)  

Thus;

x = molar solubility

  = √ (5.1 x 10^-9)

  = 7.1 x 10^-5 M  

Therefore;

Mass BaCO3 = 7.1 x 10^-5 M x 1 L x 197.34 g/mol

                      = 0.014 g

3 0
3 years ago
A student finds a rock on the way to school. In the laboratory he determines that the volume of the rock is 22.7 mL, and the mas
kari74 [83]

Answer:

The density will be 1.48 g/ mL.

Explanation:

3 0
3 years ago
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