Answer:
0.0097 mol·L⁻¹
Explanation:
The balanced equation is
2NOCl ⇌ 2NO₂ + Cl₂
Data:
Your value of Kc is incorrect. It should be
Kc =1.6 × 10⁻⁵
[NOCl] = 0.50 mol·L⁻¹
[NO] = 0.00 mol·L⁻¹
[Cl₂] = 0.00 mol·L⁻¹
Calculations:
1. Set up an ICE table.
2. Calculate the equilibrium concentrations
This is a cubic equation. Some calculators can solve cubic equations, but we can solve it by the method of successive approximations.
We will make changes to the right-hand side until the calculated value of x no longer changes,
(a) 1st approximation
Assume that 2x is negligible compared to 0.50. Then
(b) 2nd approximation
Assume that x= 0.010. Then
(b) 3rd approximation
Assume that x= 0.0097. Then
No change, so x = 0.0097.
[Cl₂] = x mol·L⁻¹ = 0.0097 mol·L⁻¹
Check:
It checks.
60mol O2 × 1 mol C6H12O6 / 6 moles 02 = 10 moles of Glucose
Answer:
Genotypic ratio = 1 Bb: 1 bb
Phenotypic ratio = 1 black rabbit : 1 brown rabbit
Explanation:
This question involves a gene coding for hair color in rabbits. The allele for Black hair (B) is dominant to the allele for brown hair (b).
According to this question, a black rabbit whose mother is brown haired (bb) is crossed with a brown hair rabbit. This means that the black rabbit will have a genotype 'Bb' while the brown rabbit will have a genotype 'bb'. Each parent will produce the following gametes:
Bb - B and b
bb - b and b
Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:
Bb, Bb, bb and bb
This means that the;
Genotypic ratio = 1 Bb: 1 bb
Phenotypic ratio = 1 black rabbit : 1 brown rabbit