3 years ago

In the reaction of 6 moles of CH4 with excess oxygen how many moles of water could be produced

1 answer:

6 0

The answer lies in the stoichiometry of the reaction. If u look at the number BEFORE the reagent u will see the ratios of the reagents.

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A piece of metal with a mass of 611 g is placed into a graduated cylinder that contains 25.1 ml of water, raising the water leve

jeka94

Mass of metal piece is 611 g and volume of graduated cylinder is 25.1 mL. When metal piece is placed in the graduated cylinder water level increases to 56.7 mL. The increase in volume is due to volume of metal piece that gets added to the volume of water.

Thus, volume of metal piece can be calculated by subtracting initial volume from the final one.

$V_{metal}=V_{final}-V_{initial}=(56.7-25.1)mL=31.6 mL$

Thus, volume of metal piece will be 31.6 mL. The mass of metal piece is given 611 g, density of metal can be calculated as follows:

$d=\frac{m}{V}=\frac{611 g}{31.6 mL}=19.33 g/mL$

Therefore, density of metal is 19.33 g/mL.

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3 years ago

You have 1 mole of a gas at STP. If you apply the ideal gas law what is the approximate volume of the gas?

goldfiish [28.3K]

Answer:

A) 22.4L

Explanation:

we know, ideal gas law states

PV=nRT

V=nRT/P

At STP,

T= 273.15K P=1atm R=0.082L.atm/mol/K n=1 mole

V=(1*0.082*273.15)/ 1

V=22.4L

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Which kind of investigations allow for the control of variables?

Butoxors [25]

Answer:

the answer to this is O hypothesis

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Describe the differences between polyp and medusa

stealth61 [152]

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The other difference is that some animals have medusa in their life or polp in their life cycle.

Hope these two differences helps :D

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