Colligative
properties calculations are used for this type of problem. Calculations are as
follows:<span>
ΔT(freezing point) = (Kf)m
ΔT(freezing point)
= 1.86 °C kg / mol (0.50 mol/kg)
ΔT(freezing point) = 0.93 °C
Tf - T = 0.93 °C
<span>T = -0.93 °C</span></span>
Answer:
the water is diffrent because it is now a gas not a liquid
Explanation:
What are you trying to ask
Answer:
The correct answer is physical properties and/or phase properties.
Explanation:
Chemical properties can alter the substance (if you burn wood, it becomes ash and is no longer wood).
Reactive properties are also chemically changing the substance.
Phase properties are where the element can be in solid, liquid, or gas form so these could also be an answer.
Answer:
1027.9 mL
Explanation:
Formula P1 x V1 / T1 = P2 x V2 / T2
Fill in what you know
Pressure is constant so no need to put that in making the formula
V1 / T1 = V2 / T2
Voulme 1= 950 mL
Volume 2= ?
Temperature 1 = 25 C
Temperature 2 = 50 C
Explanation:
Formula P1 x V1 / T1 = P2 x V2 / T2
Fill in what you know
Pressure is constant so no need to put that in making the formula
V1 / T1 = V2 / T2
Voulme 1= 950 mL
Volume 2= ?
Temperature 1 = 25 C
Temperature 2 = 50 C
