Answer:
Explanation:
Hello there!
In this case, according to the given information of the solubility of copper chloride, as the maximum amount of this salt one can dissolve without having a precipitate, we infer that since just 73 grams are actually dissolved, the following amount will remain solid as a precipitate:
Best regards!
Answer: 1.32
Explanation:
First, we must obtain the molar mass of HBr. After that, we try to obtain the concentration of the hydrobromic acid from the formula n=CV since the volume of solution and mass of acid was provided. Recall that n=m/M. If the concentration of acid is thus obtained, we make use of the fact that the concentration of H+ in the acid is equal to the molar concentration of HBr to obtain the pH. The pH is the negative logarithm of the concentration we obtained in the initial step.
Answer: 25.13 g of and 20.56 g of
will be produced from 45.70 g of
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
1 mole of produce = 1 mole of
Thus 0.571 moles of will require=
of
Mass of
1 mole of produce = 2 moles of
Thus 0.571 moles of will require=
of
Mass of
Thus 25.13 g of and 20.56 g of
will be produced from 45.70 g of