Answer:
A) Devices that transfer kinetic energy have a source of power that is in motion
Kinetic energy is the energy in motion, as such, a device that transfers kinetic energy transfers the energy the power source has into other energy forms
B) Kerosene does not easily cold start like diesel which can burn after compression
C) The first law of thermodynamics states that energy is conserved and it can neither be created nor destroyed, but can be changed from one form to another.
Therefore, when energy is not available in a given location or body, it cannot be obtained from that body or location
Explanation:
Answer:
0
Explanation:
An image of the lewis structure of the compound OF2 is shown in the image attached.
A Lewis structure is a structure in which electron pairs on atoms are shown as dots. Sometimes shared electron pairs are shown by a horizontal straight line connecting the two atoms involved.
OF2 has no double bonds as shown in its structure. It is a compound containing only two O-F sigma bonds and no pi-bonds.
Hello,
I believe that your answer would be <span>B. water freezes
</span>Hope this helps
Answer:
Both roots are imaginary roots.
Explanation:
Consider these things:
If we try to solve x²+1 = 0, notice that we aren't able to solve the equation in Real Number system because there are no negative outputs for quadratic function.
Remember that quadratic function has range greater or equal to the max-min value.
x-axis plane represents the solutions of that equation. If a graph intersects x-axis plane then it has a solution.
While a graph that doesn't have any intersects on x-plane, it means that the equation for that graph doesn't have real solutions but imaginary solutions.
As you may notice some of parabola graph has one intersect, two intersects or none. One intersect is one solution to the equation — Two intersects are two solutions of the equation and lastly, no intersects mean that no real solutions and remain only imaginary solution.
Data:




<span>
Formula: Dilution Calculations
</span>

<span>
Solving:
</span>





<span>
</span>