Answer:
When a ray of light passes through a glass slab of a certain thickness, the ray gets displaced or shifted from the original path. This is called lateral shift/displacement.
Explanation:
.
Answer: Conduction- Touch transfer heat and Earth warms air
Convection- liquid/gas transfers heat and warm air rises
Radiation- Sun heats Earth and Waves transfer heat
Explanation:
Answer:
The time taken for the ball to get to the batter is 0.41 s.
Explanation:
Given;
initial velocity of the baseball, u = 45 m/s
horizontal distance between the pitcher and the batter, X = 18.39 m
The horizontal distance or range of a projectile is given as;
X = ut
where;
t is the time of flight
u is the initial velocity
t = X / u
t = 18.39 / 45
t = 0.41 s
Therefore, the time taken for the ball to get to the batter is 0.41 s.
The directions of magnetic force and magnetic field lines are shown in the figure.
The direction to find out the magnetic field lines is given by right hand curl rule. If the thumb shows the direction of current, then the curling fingers show the direction of magnetic field lines.
The direction of force can be given by right hand thumb rule, where
Thumb - Direction of magnetic field lines
Forefinger - Magnetic
force
Centre finger -
Current
Such that forefinger, centre finger and thumb must be at 90 degrees to each other.
Answer:
The gravitational potential energy of a system is -3/2 (GmE)(m)/RE
Explanation:
Given
mE = Mass of Earth
RE = Radius of Earth
G = Gravitational Constant
Let p = The mass density of the earth is
p = M/(4/3πRE³)
p = 3M/4πRE³
Taking for instance,a very thin spherical shell in the earth;
Let r = radius
dr = thickness
Its volume is given by;
dV = 4πr²dr
Since mass = density* volume;
It's mass would be
dm = p * 4πr²dr
The gravitational potential at the center due would equal;
dV = -Gdm/r
Substitute (p * 4πr²dr) for dm
dV = -G(p * 4πr²dr)/r
dV = -G(p * 4πrdr)
The gravitational potential at the center of the earth would equal;
V = ∫dV
V = ∫ -G(p * 4πrdr) {RE,0}
V = -4πGp∫rdr {RE,0}
V = -4πGp (r²/2) {RE,0}
V = -4πGp{RE²/2)
V = -4Gπ * 3M/4πRE³ * RE²/2
V = -3/2 GmE/RE
The gravitational potential energy of the system of the earth and the brick at the center equals
U = Vm
U = -3/2 GmE/RE * m
U = -3/2 (GmE)(m)/RE