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Akimi4 [234]
3 years ago
8

A conglomerate is a rock that forms as a result of _____. . . Choices:Intense heat and pressure. Compaction and cementation. Rap

id cooling. Slow cooling.
Physics
2 answers:
sergeinik [125]3 years ago
7 0

A conglomerate is a rock that forms as a result of compaction and cementation. The correct answer between all the choices given is the first choice or letter A. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

12345 [234]3 years ago
5 0

A conglomerate is a rock that forms as a result of compaction and cementation.

Conglomerate rock is a type of sedimentary rock which are formed as a result of compaction and cementation.

<h2>Further Explanation</h2><h3>Rock </h3>
  • A rock is a naturally occurring substances that is a solid mixture of one or more minerals together with organic matter.
  • Rocks are classified based on the chemical composition, texture and the way they are formed.  
<h3>Rock cycle</h3>
  • One type of rock may change from one form to another through a rock cycle.
  • Rock cycle is the process through each various rocks change from one form to another, normally an interchange between the three major types of rocks.
<h3>Major classification of rocks:</h3><h3>Sedimentary rocks </h3>
  • Sedimentary rocks are types of rocks that are formed through accumulation of sediments at low temperatures in tectonic layers and sinks. The process involved include compaction and cementation of sediments.
  • These sediments includes; pebbles, shells, sand and other material fragments.  
  • The sediments accumulates in layers and then harden into rocks over a period of time.
  • Examples of sedimentary rocks include; limestone and conglomerate
<h3>Metamorphic rocks</h3>
  • These are types of rocks that are formed as a result of changes that occurs due to intense heat and pressure under the surface of the earth. They result from action of heat and pressure on other rocks that pre-existed.
  • These types of rocks are characterized by shiny crystals, ribbon-like layers among other features.
  • Examples of metamorphic rocks are marble and gneiss
<h3>Igneous rocks </h3>
  • These are types of rocks that are formed as a result hardening and cooling of magma from volcanic eruptions. Magma may cool inside the earth or when on the surface of the earth as a result of volcanic eruptions. The lava from this eruptions cools and hardens to form metamorphic rocks.
  • Igneous rocks are glass-like and shiny with no crystals. They may also have tiny spaces and holes due to gas bubbles trapped during the cooling process.
  • Examples of igneous rocks include obsidian and basalt.

Key words: Rocks, chemical composition, sedimentary rocks, conglomerate.

<h3>Learn more about;</h3>
  • Rocks and rock types; brainly.com/question/2817889
  • Sedimentary rocks; brainly.com/question/2817889
  • Igneous rocks; brainly.com/question/2817889
  • Metamorphic rocks; brainly.com/question/2817889

Level; High school

Subject: Geography

Topic:  Rocks

sub-topic: classification of rocks

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EastWind [94]

Answer:

Psm = 30.66 [Psig]

Explanation:

To solve this problem we will use the ideal gas equation, recall that the ideal gas state equation is always worked with absolute values.

P * v = R * T

where:

P = pressure [Pa]

v = specific volume [m^3/kg]

R = gas constant for air = 0.287 [kJ/kg*K]

T = temperature [K]

<u>For the initial state</u>

<u />

P1 = 24 [Psi] + 14.7 = 165.47[kPa] + 101.325 = 266.8 [kPa] (absolute pressure)

T1 = -2.6 [°C] = - 2.6 + 273 = 270.4 [K] (absolute Temperature)

Therefore we can calculate the specific volume:

v1 = R*T1 / P1

v1 = (0.287 * 270.4) / 266.8

v1 = 0.29 [m^3/kg]

As there are no leaks, the mass and volume are conserved, so the volume in the initial state is equal to the volume in the final state.

V2 = 0.29 [m^3/kg], with this volume and the new temperature, we can calculate the new pressure.

T2 = 43 + 273 = 316 [K]

P2 = R*T2 / V2

P2 = (0.287 * 316) / 0.29

P2 = 312.73 [kPa]

Now calculating the manometric pressure

Psm = 312.73 -101.325 = 211.4 [kPa]

And converting this value to Psig

Psm = 30.66 [Psig]

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A small block with mass 0.200 kg is released from rest at the top of a frictionless incline. The block travels a distance 0.796
Agata [3.3K]

Answer:

distance travelled by the block is 0.796 m

{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }

Explanation:

Given that;

mass of block m = 0.200 kg

distance travelled d = 0.796 m

time t = 2.00 s

m₂ = 0.400 kg

If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?

Now, using the second equation of motion;

d = ut + (\frac{1}{2} × at²)

as the object started from rest, u=0

so, we substitute

0.796  = 0×2 + (\frac{1}{2} × a(2)²)

0.796  = 0 + (\frac{1}{2} × 4a)

0.796  = 2a

a = 0.796 / 2

a = 0.398 m/s²

using first equation of motion

V_{f} = u + at

we substitute

V_{f} = 0 + 0.398 × 2

V_{f} = 0.796 m/s

now, average velocity is given as;

V_{avg} = ( 0.796 m/s  + 0 ) / 2

V_{avg} = ( 0.796 m/s  + 0 ) / 2

now, distance as the block moves in 2s will be;

D = [( 0.796 m/s  + 0 ) / 2 ] × 2

D = 0.796 m

Therefore, distance travelled by the block is 0.796 m

{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }

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