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Artemon [7]
3 years ago
13

I need help with this question really urgent

Physics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

Cost Per Hour:

132.0000

Cost Per Day:

39600.0000

Cost Per Month:

1204632.00

Cost Per Year:

14455584.00

kWh Per Day:

3600.00

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The drawing shows a model for the motion of the human forearm in throwing a dart. Because of the force M applied by the triceps
Serga [27]

Answer:

464.3 N

Explanation:

Given parameters are:

I = 0.065 kg*m^2

L = 0.025 m

R = 0.28 m

v_0 = 0 m/s

v_f = 5 m/s

t = 0.1 s

v_f=v_0+at=at

Hence, a=v_f/t

We must connect two torque equations to find the answer.

\tau=LM=I\alpha

Where \alpha =\frac{a}{R} =\frac{v_f}{Rt}

Hence, LM=I\frac{v_f}{Rt}

Thus, M = \frac{Iv_f}{LRt} = \frac{0.065*5}{0.025*0.28*0.1} =464.3 N

5 0
4 years ago
8.
svetoff [14.1K]

Answer:

9.5 seconds

Explanation:

You need to make the ending speed into meters per sec.

So it would be 120km/h = 33.33m/s

If the acceleration rate is 3.5m/s, then the final answer would equal to 9.5 seconds

Also btw rounding it up is a good idea too so 10 seconds if you round

8 0
3 years ago
An object with a resistance of 28 Ω has 76 V applied to it. How much electric current is going through this object? Answer in un
12345 [234]

Answer : The electric current of a circuit is, 2.8 A.

Explanation :

Using Ohm's law :

V=I\times R

Or,

I=\frac{V}{R}

where,

R = resistance of a circuit = 28 Ω

V = voltage of circuit = 76 volts = 76 V

I = current flowing in a circuit = ?

Now put all the given values in the above formula, we get :

I=\frac{V}{R}

I=\frac{76V}{28\Omega }

I=2.8A

Therefore, the electric current of a circuit is, 2.8 A

5 0
3 years ago
If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in
Anit [1.1K]
For the answer to the question above, 
<span>Q = amount of heat (kJ) </span>
<span>cp = specific heat capacity (kJ/kg.K) = 4.187 kJ/kgK </span>
<span>m = mass (kg) </span>
<span>dT = temperature difference between hot and cold side (K). Note: dt in °C = dt in Kelvin </span>

<span>Q = 100kg * (4.187 kJ/kgK) * 15 K </span>
<span>Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal</span>
6 0
3 years ago
Okay please help me all my assignments are due tomorrow! I need to know 5 examples of all 6 simple machines that can be found in
iren [92.7K]

Answer:

Inclined Plane – A ramp, for example a wheelchair ramp. Paired inclined planes make a pitched roof.

Wheel & Axle – On lawnmowers and wheelbarrow. Also, found in cabinet door glides and on appliances. Another common example – door knobs and even inside those locksets.

Lever – The bottle opener. Tools – the crowbar, and scissors or pliers. Double Levers – a door, a toilet seat, a broom.

Pulley – Old wood windows, some garage doors, workshop or garage lifting systems.

Wedge – The shim – used throughout the home in construction. For example, when installing doors, windows, cabinets, etc. Sometimes used to level furniture or chairs.

Screw – Like the wedge, above, well, you couldn’t build a house without screws. Certain types of plumbing valves. Plus, a jar lid is a popular example.

Now for deeper look at the simple machines found around our homes.

The hope this will be helpful.

3 0
3 years ago
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