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3 years ago

The effective nuclear charge for an atom is less than the actual nuclear charge due to

Chemistry

1 answer:

Irina18 [472]3 years ago

3 0

Answer:

A = shielding.

Explanation:

The addition of electron causes the atomic size increase from top to bottom due to increase in atomic number.

As the atomic number increased one more electron is added and because of this electron on more electronic shell is added. Thus the electron become more away from the nucleus as many of other electrons are present in the way from nucleus to the outer electrons.

The hold of nucleus becomes weaker. Although nuclear charge is also increased but at the same time other electrons shield the respective electrons. So effective nuclear charge is weaker than the actual nuclear charge.

Because of this shielding it is easy to remove the electrons or we can say ionization energy decreases.

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When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 10.085 g at 20ºC. If the d

Arte-miy333 [17]

The percentage error is the error of the measured value to the true value. To find he percent error, the equation is as follows:

Percent error = |Measured Value - True Value|/True Value * 100
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3 years ago

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siniylev [52]

Answer:

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Explanation:

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3 years ago

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slavikrds [6]

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3 years ago

If you have 3cm of each substance, which would have the MOST MASS

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2 years ago

The value of ΔH for the reaction below is -72 kJ. __________ kJ of heat are released when 1.0 mol of HBr is formed in this react

eimsori [14]

Answer:

36 KJ of heat are released when 1.0 mole of HBr is formed.

Explanation:

By Hess law,

The heat of any reaction ΔH for a specific reaction is equal to the sum of the heats of reaction for any set of reactions which in sum are equivalent to the overall reaction:

H 2 (g) + Br 2 (g) → 2HBr (g) ΔH = -72 KJ

This is the energy released when 2 moles of HBr is formed from one mole each of H2 and Br2.

Therefore, Heat released for the formation of 1 mol HBr would be half of this.

Hence,

ΔHreq = -36 kJ

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2 years ago