Answer:
what? can you translate it in english
Explanation:
I have no explanation and i have no idea
A strong acid- strong base titration is performed using a phenolphthalein indicator. Phenolphtalein is chosen because it changes color in a pH range between 8.3 – 10. It will appear pink in basic solutions and clear in acidic solutions. ... It is known as the titrant.
A CH compound is combusted to produce CO2 and H2O
CnHm + O2 -----> CO2 + H2O
Mass of CO2 = 23.1g
Mass of H2O = 10.6g
Calculate by mass of the compounds
For Carbon C, divide by molecular weight of CO2 and multiply with Carbon
molecular weight. So C in grams = 23.1 x (12.01 / 44.01) = 6.3 g C
For Hydrogen H, divide by molecular weight of H2O and multiply with Hydrogen molecular weight. So H in grams = 10.6 x (2.01 / 18.01) = 0.53 g C
= 1.18 of H
Calculate the moles for C and H
6.3 grams of C x (1 mole/12.01 g C) = 0.524 moles of C
1.18 grams of H x (1 mole/1.008 g H) = 1.17 moles of H
Divides by both mole entities with smallest
C = 0.524 / 0.524 = 1 x 4 = 4
H = 1.17 / 0.524 = 2.23 x 4 = 10
The empirical formula is C4H10.
It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.
<u>Explanation:</u>
2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂
We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.
![100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}](https://tex.z-dn.net/?f=100%20g%20%5Ctext%20%7B%20of%20%7D%20A%20g%20N%20O_%7B3%7D%20%5Ctimes%20%5Cfrac%7B2%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20N%20O_%7B3%7D%7D%7B169.87%20g%20A%20g%20N%20O_%7B3%7D%7D%20%5Ctimes%20%5Cfrac%7B2%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20C%20l%7D%7B1%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20N%20O_%7B3%7D%7D%20%5Ctimes%20%5Cfrac%7B143.32%20g%20A%20g%20C%20l%7D%7B1%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20C%20l%7D)
= 337.5 g AgCl
In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.
It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.