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stealth61 [152]
4 years ago
8

Sound travels faster through rigid material like steel rather than through spongy materials like rubber. Why?

Physics
1 answer:
drek231 [11]4 years ago
3 0
<span>since sound travels using mechanical waves and needs a material medium to propagate and since mechanical waves spread through vibrations ...and since hard materials have their atoms packed closely....they need to vibrate with a smaller amplitude to pass on the wave....thus sound travels faster in a denser medium than a less dense one.</span>
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Find the kinetic energy ofan electron that moves at half the speed of light to four significant digits.
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Answer:

Ke=electron kinetic energy=10.24*10^{33} J

Explanation:

The electron has a mass of 9.1*10^{-31} kg

The speed of light in a vacuum is a universal constant with the value 299 792 458 m / s (186 282,397 miles / s), although it is usually close to 3*10^{8} \frac{m}{s}

Kinetic energy (K) is the energy associated with bodies that are in motion, depends on the mass and speed of the body and is calculated using the formula:

K=\frac{1}{2} *m*v^{2}        Equation(1)

K=kinetic energy (J)

m =mass of the body (kg)

v= speed of the body(\frac{m}{s} )

for this problem We replace in the equation (1)

me=9.1*10^{-31} kg = electron mass

ve=1.5*10^{8} \frac{m}{s}=Half the speed of light

=electron speed

We replace in  the  equation (1) :

Ke=\frac{1}{2}*me*ve^{2}

Ke=\frac{1}{2} *9.1*10^{-31} *(1.5*10^{8} )^{2}

Ke=4.55*10^{-31} *(1.5)^{2} *(10^{8} )^{2}

Ke=10.24*10^{33} J

The energy kinetic of the electron is 10.24*10^{33} Joules

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3 years ago
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m
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Answer:

1) The time it takes the diver to move off the end of the diving board to the pool surface, t_w, is approximately 1.392 seconds

2) The horizontal distance from the edge of the pool to where the diver enters the water, d_w, is approximately 5.76 meters

Explanation:

1) The given parameters are;

The height of the diving board above the pool's surface, h = 9.5 m

The length by which the diving board over hangs the pool L = 2 m

The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s

Taking t_w = The time it takes the diver to move off the end of the diving board to the pool surface

Therefore, we have from the equation of free fall;

h = 1/2 × g × t_w²

Where;

g = The acceleration due to gravity = 9.81 m/s²

Substituting the values, gives;

9.5 = 1/2 × 9.81 × t_w²

t_w = √(9.5/(1/2 × 9.81)) ≈ 1.392 s

The time it takes the diver to move off the end of the diving board to the pool surface = t_w ≈ 1.392 s

2) The horizontal distance, d_w, in meters from the edge of the pool to where the diver enters the water is given as follows;

d_w = L + v₀ × t_w = 2 + 2.7× 1.392 ≈ 5.76 m

∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.

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