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hodyreva [135]
3 years ago
15

in a plantation,there are 230 trees in a row. There are at least 3 papaya trees between any 2 rambutan trees. What is the larges

t possible number of rambutan trees in that row?​
Mathematics
1 answer:
Zinaida [17]3 years ago
7 0

Answer:

  58

Step-by-step explanation:

The total number of trees in a row that starts and ends with a rambutan tree is ...

  4n -3 . . . . for n rambutan trees

So, the number of rambutan trees that there can be in a row of 230 trees is ...

  4n -3 ≤ 230

  4n ≤ 233

  n ≤ 233/4 = 58 1/4

The largest possible number of rambutan trees in a row of 230 trees is 58.

_____

1 rambutan tree: R . . . n=1, tree count = 1

2 rambutan trees: RpppR . . . n=2, tree count = 5

3 rambutan trees: RpppRpppR . . . n=3, tree count = 9

The tree count is an arithmetic sequence with first term 1 and common difference 4. Then the n-th term of the sequence is ...

  tn = a1 +d(n -1) = 1 +4(n -1) = 4n -3

Term 58 is ...

  t58 = 4·58 -3 = 229

So, the row of trees might be ...

  RpppRppp ... RpppRpppRp . . . . with 58 R and 172 p.

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one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units. are these two figures scaled versio
Amanda [17]

Answer: The both triangle are not scale version to each other.

Explanation:

It is given that the one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units.

The two shapes are scaled version of each other if their corresponding sides are in same proportion. In other words the if two shapes scaled version of each then the shapes are similar.

The sides or first rectangle are 2 and 7. The measures of second rectangle are 11 and 37.

The proportion of small side is,

\frac{2}{11}

The proportion of large side is,

\frac{7}{37}

So,

\frac{2}{11}\neq \frac{7}{37}

Since the proportion are not equal, therefore  both triangle are not scale version to each other.

6 0
3 years ago
Replace? with =, >, or < to make the statement true. 16 ÷ 4 + 12? 4 + 24 ÷ 2
AleksAgata [21]
<em><u>16/4+12 ? 24/2</u></em>
<em><u>4+12 ? 12</u></em>
<em><u>16 ? 12</u></em>
<em><u>?=></u></em>

<em><u>ANSWER: A - ></u></em>
6 0
3 years ago
Find f(-5)<br> f(x) = -4x + 3<br><br> A) -17 <br> B) -7 <br> C) 12 <br> D) 23
Andrew [12]

Answer:

B

Step-by-step explanation:

=tyhgff GJ jhvcvvbvcccvjuuuu hgfdvghg jhvgfgg bbvcfff bbvcfff bbvcfff hbbjggg hhfccgyhb 5th and 3rd of November in a rectangle has been released in December 5th of July in a square of the area and I am very interested to the area and I look for the position and am looking forward for the position of your firm in my work to be a great fit and would love ms your help and if I could help with any other things

3 0
2 years ago
Find the first term and the common ratio <br>third term =6 and seventh term= 96​
mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: a_n= a_1r^{n-1}

We are given: third term = 6 i,e

a_3=a_1r(3-1)\\6=a_1r^2----eq(1)

Seventh term = 96

a_7=a_1r(7-1)\\96=a_1r^6----eq(2)

Dividing eq(2) and eq(3)

\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}

So, Common Ratio r = 2

Finding First term using eq(1)

a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}

So, First term a₁ = 3/2 and common ratio r = 2

6 0
3 years ago
Vertex B is located at ( ____, ____ ).<br> This is all it said no image
OLEGan [10]

Answer:

i believe its B= (1,5)

Step-by-step explanation:

7 0
3 years ago
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