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hodyreva [135]
3 years ago
15

in a plantation,there are 230 trees in a row. There are at least 3 papaya trees between any 2 rambutan trees. What is the larges

t possible number of rambutan trees in that row?​
Mathematics
1 answer:
Zinaida [17]3 years ago
7 0

Answer:

  58

Step-by-step explanation:

The total number of trees in a row that starts and ends with a rambutan tree is ...

  4n -3 . . . . for n rambutan trees

So, the number of rambutan trees that there can be in a row of 230 trees is ...

  4n -3 ≤ 230

  4n ≤ 233

  n ≤ 233/4 = 58 1/4

The largest possible number of rambutan trees in a row of 230 trees is 58.

_____

1 rambutan tree: R . . . n=1, tree count = 1

2 rambutan trees: RpppR . . . n=2, tree count = 5

3 rambutan trees: RpppRpppR . . . n=3, tree count = 9

The tree count is an arithmetic sequence with first term 1 and common difference 4. Then the n-th term of the sequence is ...

  tn = a1 +d(n -1) = 1 +4(n -1) = 4n -3

Term 58 is ...

  t58 = 4·58 -3 = 229

So, the row of trees might be ...

  RpppRppp ... RpppRpppRp . . . . with 58 R and 172 p.

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LA BASE DE UN RECTANGULO ES 8 M MAYOR QUE LA ALTURA, EL AREA MIDE 65 METROS CUADRADOS ¿CUANTO MIDEN LA BASE Y ALTURA?
sp2606 [1]

Answer:

23 m and 15 m

Step-by-step explanation:

THE BASE OF A RECTANGLE IS 8 M GREATER THAN THE HEIGHT, THE AREA MEASURES 65 SQUARE METERS HOW MUCH DO THE BASE AND HEIGHT MEASURE?

Let the height of the rectangle is h.

Base = 8+h

Area of the rectangle, A = 65 m²

We need to find the base and height of the rectangle. The area of a rectangle is given by :

A = bh

So,

65=(8+h)\times h\\\\65=8h+h^2\\\\h^2+8h-65=0\\\\(h-5)(h+13)=0\\\\h=5\ m\ \text{and}\ x=-13\ m

Neglecting negative value, h = 15 m

Base  = 8+15 = 23 m

So, the base and height of the rectangle is 23 m and 15 m respectively.

4 0
3 years ago
In triangle QRS the measurement of an angle RSQ is 29.1 and the measure of angle QRS is 70 degrees what is the measurement of sq
Katen [24]

Answer: The measure of ∠SQR= 80.9°

Step-by-step explanation:

Given: In triangle QRS,

∠ RSQ = 29.1° and ∠QRS=70°

To find: ∠SQR

Angles sum property of triangle = Sum of all the angles in a triangle is 180°.

For Δ QRS,

∠SQR + ∠ RSQ +∠QRS = 180°

⇒ ∠SQR + 29.1° + 70° = 180°

⇒ ∠SQR + 99.1° = 180°

⇒ ∠SQR= 180°-99.1

⇒ ∠SQR= 80.9°

Hence, the measure of ∠SQR= 80.9°

4 0
3 years ago
In a company 37% of the 1500 employees are females work out the number of males in the company
kondaur [170]
100-37=63
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Step-by-step explanation:

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3 years ago
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euben's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Reuben $5.70 per pound, and type
Kobotan [32]

Answer:

The quantity of type A coffee is 73 pounds

The quantity of type B coffee is 94 pounds .

Step-by-step explanation:

Given as :

The price of Type A coffee costs = $ 5.70 per pound

The price of Type B coffee costs = $ 4.30 per pound

The total quantity of coffee does Reuben purchases = 167 pounds

The total cost of the coffee for 167 pounds = $ 820.30

Let The quantity for type A coffee = a pounds

And The quantity of type B coffee = b pounds

Now, <u>According to question</u>

a + b = 167 pounds      And

$ 5.70 × a + $ 4.30 × b = $ 820.30

Now solving equations

5.70 × ( a + b ) = 5.70 × 167

or, 5.70 a + 5.70 b = 951.9

Now ,

( 5.70 a + 5.70 b ) - (   5.70  a +  4.30  b ) = 951.9 - 820.30

or, ( 5.70 a - 5.70 a ) + ( 5.70 b - 4.30 b ) = 131.6

Or, 0 + 1.4 b = 131.6

∴ b = \frac{131.6}{1.4}

I.e b = 94 pounds

Put the value of b to get a value

So, a = 167 pounds - b

Or, a = 167 - 94

∴   a = 73 pounds

Hence The quantity of type A coffee is 73 pounds

And The quantity of type B coffee is 94 pounds   .  Answer

4 0
3 years ago
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