a cliff diver drops from rest to the water below. how many seconds does it take for the diver to go from 0 to 60. that is to go
1 answer:
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Answer:
0.304 m/s2
Explanation:
If the first child is pushing with a force of 69N to the right and the 2nd child is pushing with a force of 91N to the left. Then the net pushing force is 91 - 69 = 22 N to the left. Subtracted by 15N friction force then the system of interest is subjected to F = 7 N net force tot he left.
We can use Newton's 2nd law to calculate the net acceleration of the system
Answered using calculus.
Antidifferentiated the acceleration to get velocity. Added variable c as we do not know if there was an extra number there yet.
Knowing that when time is 0, the velocity is 20, we can substitute those numbers into the equation and find that c = 20.
Now we have full velocity equation: v = 1.5t + 20
Now we substitute 4 into t to find out the velocity after 4 seconds. This gives us the final answer of 26m/s
Antidifferentiated the acceleration to get velocity. Added variable c as we do not know if there was an extra number there yet.
Knowing that when time is 0, the velocity is 20, we can substitute those numbers into the equation and find that c = 20.
Now we have full velocity equation: v = 1.5t + 20
Now we substitute 4 into t to find out the velocity after 4 seconds. This gives us the final answer of 26m/s
Answer:
Time taken, t = 30.15 minutes
Explanation:
It is given that,
Distance from the center of planet, r = 40 miles
Speed of the shuttle, v = 500 miles per hour
Let t is the time taken by it to complete one full orbit. The displacement of the shuttle is,
d = 251.32 miles
Now time can be calculated using the expression for the velocity as :
t = 0.50264 hours
or
t = 30.15 minutes
So, the shuttle will take 30.15 minutes to complete one full orbit. Hence, this is the required solution.