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kipiarov [429]
3 years ago
11

Which is a freshwater region characterized as a large standing body of water? A. lake B. river C. ocean D. stream

Physics
2 answers:
prisoha [69]3 years ago
5 0

Answer:

A. Lake

Explanation:

We need to recall that the water which contains less than 1% salts is called as freshwater.

In lakes water comes from rain, melting of ice from mountains, seepage of ground water, and water streams. These all are fresh sources of water. Therefore, A is the right answer.  

B is not the right answer because river water dissolves salts while passing through the stones and riverbeds. So, water is not always fresh in rivers.  

C is not correct, because ocean water contains a huge amount of salts.

Although streams have fresh water but they also have small size. Therefor, D is also not right answer.

Alexus [3.1K]3 years ago
4 0
This is A.) lake. A river is a small amount of water that isn't always fresh water. A stream is too small. And an ocean is made of salt water.
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A concrete block is hung from an ideal spring that has a force constant of 100 N/m . The spring stretches 0.129 m .A- What is th
madam [21]

Answer:

1.31498 kg

0.72050 s

0.72050 s

Explanation:

m = Mass of block

g = Acceleration due to gravity = 9.81 m/s²

k = Spring constant = 100 N/M

x = Displacement = 0.129 m

The force balance is

mg=kx\\\Rightarrow m=\dfrac{kx}{g}\\\Rightarrow m=\dfrac{100\times 0.129}{9.81}\\\Rightarrow m=1.31498\ kg

The mass of the block is 1.31498 kg

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{1.31498}{100}}\\\Rightarrow T=0.72050\ s

The period of oscillations is 0.72050 s

The time period does not depend on the acceleration due to gravity. It varies with the mass and the spring constant.

Hence, the time period would be the same

8 0
3 years ago
A particular car can go from rest to 90 km/h in 10 s. What is its acceleration? (Report your answer in km/h*s)
Romashka-Z-Leto [24]

Answer: 9 km/h

Explanation:i’m pretty sure

5 0
4 years ago
Read 2 more answers
Which of the following statements concerning the lab is TRUE?
Over [174]

Answer:

(b) To get m3 to slide, m1 must be increased, never decreased.

Explanation:

Lab experiments require attentiveness. If there is one thing missed or not taken seriously whole experiment could go wrong. In this case to slide m3 there should be more weight at m1. If the weight of m1 is lesser than m3 then the object will not slide. It will remain at the point where there is more weight. To slide an object there must be less frictional surface and more weight placed at the desired end point.

3 0
3 years ago
What is the maximum mass that can hang without sinking from a 20-cm diameter Styrofoam sphere in water? Assume the volume of the
alex41 [277]

Answer:

the maximum mass that can hang without sinking is 2.93 kg

Explanation:

Given: details:

sphere diameter  d = 20 cm

so, radius r = 10 cm  = 0.10 m

density of the Styrofoam sphere D = 300 kg/m3

sphere volume  V = \frac{4}{3} \pi r^3

                                                   =\frac{4}{3} \pi 0.10^3

                                                   =4.18*10^{-3} m^3

we know that

Density = \frac{Mass}{Volume}

mass  M = Density * Volume

                                  = (300)(4.18*10^{-3} m3)

                                  =1.25 kg

mass of the water displace = volume *density  of water

                                                 = 4.18*10^{-3} m3 * 1000

                                                 = 4.18 kg

The difference between the mass of water and mass of styrofoam is the amount of mass that the sphere can support

=4.18 kg  -1.25 kg

= 2.93 kg

3 0
4 years ago
Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou
Mariulka [41]

Answer:

w = 1.976 rpm

Explanation:

For simulate the gravity we will use the centripetal aceleration a_c, so:

a_c = w^2r

where w is the angular aceleration and r the radius.

We know by the question that:

r = 60.5m

a_c = 2.6m/s2

So, Replacing the data, and solving for w, we get:

2.6m/s = w^2(60.5m)

W = 0.207 rad/s

Finally we change the angular velocity from rad/s to rpm as:

W = 0.207 rad/s = 0.207*60/(2\pi)= 1.976 rpm

3 0
4 years ago
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