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Wewaii [24]
3 years ago
12

A 65 kg diver jumps off a 10 m platform.

Chemistry
1 answer:
kramer3 years ago
8 0

Answer:

1. 6.37 KJ

2. 3.185 KJ

Explanation:

Gravitational potential energy is a form of potential energy with respect to the force of gravity.

Gravitational potential energy = mass x acceleration due to gravity x height

i.e   PE = m x g x h

1. At the top of the platform; mass = 65 kg, acceleration due to gravity = 10 m/s^{2}, and height = 10 m.

Gravitational potential energy = 65 x 9.8 x 10

                                                  = 6370 Joules

The gravitational potential of the diver at the top of the platform is 6.37 KJ.

2. Halfway down; mass = 65 kg, acceleration due to gravity = 10 m/s^{2}, and height = 5 m.

Gravitational potential energy = 65 x 9.8 x 5

                                                  = 3185 Joules

The gravitational potential energy of the diver halfway down is 3.185 KJ.

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1.14 M

Explanation:

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The molar mass of calcium chloride is 110.98 g/mol.

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Step 2: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

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The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?​
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Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

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Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

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N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

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Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

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