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Wewaii [24]
3 years ago
12

A 65 kg diver jumps off a 10 m platform.

Chemistry
1 answer:
kramer3 years ago
8 0

Answer:

1. 6.37 KJ

2. 3.185 KJ

Explanation:

Gravitational potential energy is a form of potential energy with respect to the force of gravity.

Gravitational potential energy = mass x acceleration due to gravity x height

i.e   PE = m x g x h

1. At the top of the platform; mass = 65 kg, acceleration due to gravity = 10 m/s^{2}, and height = 10 m.

Gravitational potential energy = 65 x 9.8 x 10

                                                  = 6370 Joules

The gravitational potential of the diver at the top of the platform is 6.37 KJ.

2. Halfway down; mass = 65 kg, acceleration due to gravity = 10 m/s^{2}, and height = 5 m.

Gravitational potential energy = 65 x 9.8 x 5

                                                  = 3185 Joules

The gravitational potential energy of the diver halfway down is 3.185 KJ.

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Answer:

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<h2>1.20 L</h2>

Explanation:

Since the concentration , mass and molar mass of NaOH has been given we use the formula

<h3>C =  \frac{m}{M \times v}</h3>

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Making volume the subject we have

<h3>v =  \frac{m}{C \times M}</h3>

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We have the final answer as

<h3>Volume = 1.20 L</h3>

Hope this helps you

8 0
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How many formula units make up 10.2 g of magnesium chloride (MgCl2)?
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Answer:

6.46×10²² formula units

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From the question given above, the following data were obtained:

Mass of MgCl₂ = 10.2 g

Number of formula units =?

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95 g of MgCl₂ = 6.02×10²³ formula units

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95 g of MgCl₂ = 6.02×10²³ formula units

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10.2 g of MgCl₂ = 6.46×10²² formula units

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