F=MA
*newton 2nd law*
F=6.75N
M=32kg
A= F/M
A=6.75/32
equal
a.0.21m/s2
The unmodulated carrier wave is going into the box, and when it comes out, its AMPLITUDE has been modulated.
Answer:

Explanation:
The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2 i.e.
and 
The wavelength of Hi line of the Balmer series is given by :




So, the wavelength for this line is 550 nm. Hence, this is the required solution.