1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LenKa [72]
2 years ago
14

A wave traveling in a string has a wavelength of 35 cm, an amplitude of 8. 4 cm, and a period of 1. 2 s. What is the speed of th

is wave?.
Physics
1 answer:
AlekseyPX2 years ago
3 0

0.29 m/s (wave velocity = wavelength (lamda)/period (T) in metres)

35 / 1.2 = 29.16

29.16 ÷ 100 = 0.29

Wave velocity in string:

The properties of the medium affect the wave's velocity in a string. For instance, if a thin guitar string is vibrated while a thick rope is not, the guitar string's waves will move more quickly. As a result, the linear densities of the two strings affect the string's velocity. Linear density is defined as the mass per unit length.

Instead of the sinusoidal wave, a single symmetrical pulse is taken into consideration in order to comprehend how the linear mass density and tension will affect the wave's speed on the string.

Learn more about density here:

brainly.com/question/15164682

#SPJ4

You might be interested in
An amusement park ride consists of a rotating circular platform 8.26 m in diameter from which 10 kg seats are suspended at the e
VashaNatasha [74]

To solve this problem we will begin by finding the necessary and effective distances that act as components of the centripetal and gravity Forces. Later using the same relationships we will find the speed of the body. The second part of the problem will use the equations previously found to find the tension.

PART A) We will begin by finding the two net distances.

r = \frac{8.26}{2} = 4.13m

And the distance 'd' is

d = lsin\theta

d = 1.14 sin 16.2\°

d = 0.318m

Through the free-body diagram the tension components are given by

Tcos\theta = mg

Tsin\theta = \frac{mv^2}{R}

Here we can watch that,

R = r+d

Dividing both expression we have that,

tan\theta = \frac{v^2}{Rg}

Replacing the values,

tan(16.2) = \frac{v^2}{(4.13+0.318)(9.8)}

v = 4.83371m/s

PART B) Using the vertical component we can find the tension,

Tcos\theta = mg

T = \frac{mg}{cos\theta}

T = \frac{(10+26.2)(9.8)}{cos(16.2)}

T = 369.42N

6 0
3 years ago
A bubble at the bottom of lake rises to surface within 10.0 seconds with an acceleration of 10.0 meters per second. What is the
amm1812
If the bubble travels 10 meters per second and it takes 10 seconds, then just multiply the distance per second by the total seconds to get the total depth.
10 • 10 = 100
The lake is 100 meters deep.

Think of it this way to clarify the answer:
It takes a bubble traveling at a speed of 10 meters per second 10 seconds to travel 100 meters.
5 0
3 years ago
A satellite dish is shaped like a paraboloid of revolution. This means that it can be formed by rotating a parabola around its a
pentagon [3]

Answer:

Explanation:

Given dish width= 48ft

Depth = 4ft

Using equation of a parabola

x²= 4py

48² = 4p 4

4p = 576

P= 144ft

Thus the the receiver should be placed 144ft from t the vertex

7 0
3 years ago
How can we maximise the rate of energy transfer to keep things cool?
faltersainse [42]
To do this we may use things that are good conductors - are painted dull black -
Have a air flow around them Maximised.


6 0
3 years ago
A 58 kg skier is going down a 35 degree slope. The areaof each
maxonik [38]

To solve this problem we will use a free body diagram that allows us to determine the Normal Force.

In general, the normal force would be equivalent to

N = mgcos\theta

Since the skier is standing on two skis, his weight will be divide by two

N' = \frac{mgcos\theta}{2}

Pressure is given as the force applied in a given area, that is

P = \frac{F}{A}

Replacing F with N'

P = \frac{N'}{A}

P = \frac{\frac{mgcos\theta}{2}}{A}

Our values are given as,

m = 58kg

g = 9.8m/s^2

\theta = 35\°

A = 0.3m^2

Replacing we have that

P = \frac{\frac{(58)(9.8)cos(35)}{2}}{0.3}

P = 776.01Pa

Therefore the pressure exerted by each ski on the snow is 776.01Pa

6 0
3 years ago
Other questions:
  • What part of the hammer acts as the fulcrum when the hammer is used to remove a nail
    11·1 answer
  • A man is pulling a 13-kg sled across a flat, snowy surface. He holds the handle of the sled at a 30° angle with the ground.
    8·1 answer
  • What is the series equivalent of two 1000 W resistors in series?
    12·1 answer
  • Fire trucks have the word FIRE written two ways, as seen here, on the front of the truck. Why is that?
    10·2 answers
  • How strongly the planet you're on pulls on you is your
    11·2 answers
  • Which state of matter would be described as a highly energized charge particles with moving extremely fast
    12·2 answers
  • A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's ti
    10·1 answer
  • Automobiles must be able to sustain a frontal impacl The automobile design must allow low speed impacts with little sustained da
    6·1 answer
  • Baggage on the floor of the baggage car of a high-speed train is not prevented from moving other than by friction. The train is
    13·1 answer
  • If an object is accelerating at 4 m/s^2 and has a mass of 8 kg, what is the net
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!