Answer:
The system's kinetic energy changes by 3.6 J
Explanation:
The given parameters are;
The number of cart = 2
The mass of each cart = 0.5kg
The initial length of the spring = 0.50 m
The final length of the spring =T0.3 m
The change in position of the first cart = 0.6 m
The energy given to the first cart = Work done by the force = Force × Displacement
The initial kinetic energy of the two cart moving together = Energy given to the first cart = 6.0 × 0.2 = 1.2J
The kinetic energy given to the two cart combined = The applied force × The total displacement of the two cart as they move together
The kinetic energy given to the two cart combined = 6.0 × (0.6 - 0.2)
The kinetic energy given to the two cart combined = 6.0 × 0.4 = 2.4 J
The total kinetic energy given to the two cart = 1.2 + 2.4 = 3.6 J
The total kinetic energy given to the two cart = 3.6 J
The system's kinetic energy changes by 3.6 J.
Answer:
0.25 gram of neptunium is remaining
Explanation:
First we calculate the no. of half lives passed. For that we have formula:
n = t/T
where,
n = no. of half lives passed = ?
t = total time passed = 8 days (From Monday noon to Tuesday noon of following week)
T = Half Life Period = 2 days
Therefore,
n = 8 days/2 days
n = 4
Now, for the remaining mass of neptunium, we use the formula:
m = (mi)/(2)^n
where,
mi = initial mass of neptunium = 4.00 grams
m = remaining mass of neptunium = ?
Therefore,
m = 4 grams/2⁴
<u>m = 0.25 gram</u>
An iron core is needed in an electromagnet because it serves to increase the magnetic field created. It has a ferromagnetic properties. <span>An </span>electromagnet<span> is essentially just a battery attached to a coil of wire wrapped around a metal</span>core<span>. </span>
Answer:
81.1 m
Explanation:
Given:
x₀ = 0 m
y₀ = y = 0 m
v₀ₓ = 29.5 cos 33.0° m/s
v₀ᵧ = 29.5 sin 33.0° m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
Find:
x
First, find the time it takes to land.
y = y₀ + v₀ᵧ t + ½ aᵧt²
0 = 0 + (29.5 sin 33.0) t - 4.9 t²
t = (29.5 sin 33.0) / 4.9
t = 3.28 s
Now in the x direction:
x = x₀ + v₀ₓ t + ½ aₓt²
x = 0 + (29.5 cos 33.0) (3.28) + 0
x = 81.1 m
The outfielder was 81.1 meters away.
