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Sever21 [200]
3 years ago
11

A baseline for an experimental investigation is provided by the

Chemistry
2 answers:
Rina8888 [55]3 years ago
8 0
A baseline for experimental investigation is provided by an hypothesis. This is a must before conducting experiments. Also, it is the hypothesis that is being proved by doing the experiments. So, hypothesis is very important in research studies. Hope this answers the question.
Thepotemich [5.8K]3 years ago
8 0

Answer: hypothesis

Explanation:

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1-<br> the<br> Nalt and Gil-<br> Cu2+<br> ad out- <br> what are the spectator ions in this reaction
Mrac [35]

Answer:

cu2 is 5he correct answer

3 0
2 years ago
1(a). What is the solubility of calcium chloride (CaCl2) at 5°C?
In-s [12.5K]

Answer:

60 g/100 g water  

Explanation:

Find 5 °C on the horizontal axis.

Draw a line vertically from that point until you reach the solubility curve for CaCl₂.  

Then draw a horizontal line from there to the vertical axis.

The solubility of CaCl₂ is 60 g/100 g water.

7 0
3 years ago
If a solution is saturated, which of these is true?
Fiesta28 [93]
If a solution is saturated, that means it already posses the maximum number of solutes thus have been dissolved in it, and thus the concentration cannot be increased.
8 0
3 years ago
Read 2 more answers
If 2.00 moles of H₂ and 1.55 moles of O₂ react how many moles of H₂O can be produced in the reaction below?
jekas [21]

Answer:

2 mol H₂O

Explanation:

With the reaction,

  • 2H₂(g) + O₂(g) → 2 H₂O(g)

1.55 moles of O₂ would react completely with ( 2*1.55 ) 3.1 moles of H₂. There are not as many moles of H₂, thus H₂ is the limiting reactant.

Now we <u>calculate the moles of H₂O produced</u>, <em>starting from the moles of limiting reactant</em>:

  • 2.00 mol H₂  * \frac{2molH_2O}{2mol H_2} = 2 mol H₂O
5 0
2 years ago
4. How would you calculate the poH of a base when given the<br><br> concentration of [OH]-?
Novay_Z [31]

Answer:

Use pOH = -log₁₀ [OH-]

Explanation:

pOH can be calculated from the concentration of hydroxide ions using the formular below:

pOH = -log₁₀ [OH-]

The pOH is the negative logarithm of the hydroxide ion concentration.

3 0
3 years ago
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