1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lions [1.4K]
3 years ago
7

PLEASE HELP ME!!! ASAP

Chemistry
1 answer:
shtirl [24]3 years ago
5 0

Answer:

Theoretical yield of the reaction = 34 g

Excess reactant is hydrogen

Limiting reactant is nitrogen

Explanation:

Given there is 100 g of nitrogen and 100 g of hydrogen

Number of moles of nitrogen = 100 ÷ 28 = 3·57

Number of moles of hydrogen = 100 ÷ 2 = 50

Reaction between nitrogen and hydrogen yields ammonia according to the following chemical equation

N2 + 3H2 → 2NH3

From the above chemical equation for every mole of nitrogen that reacts, 3 moles of hydrogen will be required and 2 moles of ammonia will be formed

Now we have 3·57 moles of nitrogen and therefore we require 3 × 3·57 moles of hydrogen

⇒ We require 10·71 moles of hydrogen

But we have 50 moles of hydrogen

∴ Limiting reactant is nitrogen and excess reactant is hydrogen

From the balanced chemical equation the yield will be 2 × 3·57 moles of ammonia

Molecular weight of ammonia = 17 g

∴ Theoretical yield of the reaction = 2 × 3·57 × 17 = 121·38 g

You might be interested in
Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25
o-na [289]
The equation Eºcell = 0.0592/n logK must be used to find n and also Eºcell 
2 Al(s) + 3 Mg2+(aq) → 2 Al3+(aq) + 3 Mg(s) Al3+ +3e- --> Al Eº = -1.66 V Mg2+ +2e- -->Mg Eº = -2.37V 
To balance the equation, 6 moles of electrons must be transferred (2 Al and 3 Mg). This will be the value of n in the equation. 
To find Eºcell, you need the reduction potentials which should be given in a table, and given above. Eºcell = -1.66 - (-2.37) = 0.71 V log K = Eºcell x n/0.0592 = 0.71 x 6/0.0592 log K = 71.95 K = 10^71.95 K = 1.1x10^72
6 0
3 years ago
Net ionic equation for Barium chloride​
vaieri [72.5K]

Answer: There is one way to write it but i’ll also provide an unbalanced equation and a balanced one.

Explanation:

Unbalanced : Ba (aq) + Cl2 (aq)—-> BaCl (aq)

Balanced : 2Ba (aq) + Cl2 (aq)—> 2BaCl(aq)

3 0
2 years ago
The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
sweet [91]

Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ni^{2+}][CN^-]^2

Now put all the given values in this expression, we get:

3.0\times 10^{-23}=(0.220+s)\times (2s)^2

s=5.84\times 10^{-12}M

Therefore, the maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

7 0
2 years ago
¿cómo se ionizan los ácidos y las bases en medio acuoso?
Vadim26 [7]

Answer:

Ei

Explanation:

De acordo com a teoria de Arrhenius, os ácidos são os compostos que se dissociam no meio aquoso para gerar os íons hidrogênio H + no meio aquoso.

4 0
3 years ago
if it takes 54 mL of 0.1 NaOH to neutralize 125 mL of an HCL solution, what is the concentration of HCL?
OleMash [197]

Answer:

0.0432M

Explanation:

We begin by writing a balanced equation for the reaction. This is illustrated below:

NaOH + HCl —> NaCl + H2O

From the equation above,

The number of mole of the acid (nA) = 1

The number of mole of the base (nB) = 1

Data obtained from the question include:

Vb (volume of the base) = 54mL

Cb (concentration of the base) = 0.1M

Va (volume of the acid) = 125mL

Ca ( concentration of the acid) =?

Using CaVa/CbVb = nA/nB, the concentration of the acid can easily be obtained as shown below:

CaVa/CbVb = nA/nB

Ca x 125 / 0.1 x 54 = 1

Cross multiply to express in linear form:

Ca x 125 = 0.1 x 54

Divide both side by 125

Ca = (0.1 x 54) / 125

Ca = 0.0432M

Therefore, the concentration of the acid is 0.0432M

3 0
3 years ago
Other questions:
  • For a gaseous reaction, standard conditions are 298 K and a partial pressure of 1 atm for all species. For the reaction 2 NO ( g
    5·1 answer
  • Is burning sugar a chemical or physical change? Please provide explanation
    12·2 answers
  • Does it matter in this problem how many eggs are in a cluckster ?
    15·1 answer
  • Cells perform many functions in living organisms. Which of the following processes occur in cells? A. extracting energy B. excre
    9·2 answers
  • Which of the following would double the pressure on a contained gas at constant temperature?
    6·1 answer
  • Which one of these compounds listed below is least likely to exist, and why?NaBr HgCl2 ArCl Mg3N2 C3H8 CaO
    14·1 answer
  • Discuss how to separate a mixture of iron fillings, salt, sand, and wood chips.
    13·1 answer
  • Assuming the metals lose all their valence electrons and the nonmetals gain electrons to complete the s-p subshells, which listi
    13·1 answer
  • YO SOMEONE ANSWER DIS ASAP I GOT 2 MINUTES
    12·1 answer
  • How to do 3 and 4 questions
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!