Possibly the amount of electrons and energy levels in which the electrons reside
Answer:
1.55
Explanation:
-log(M)=pH
- Hope that helps! Please let me know if you need further explanation.
Circulating round the nucleus are the electrons in various orbits of different energy levels. Electrons are negatively charged and represented by the symbol 'e'. In the given image the number of protons are -6. Hence the element in question is Carbon as Carbon has the atomic number 6.
<h3>
Answer:</h3>
495 g K₃N
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.77 mol K₃N
<u>Step 2: Identify Conversions</u>
Molar Mass of K - 39.10 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 3.77 \ mol \ K_3N(\frac{131.31 \ g \ K_3N}{1 \ mol \ K_3N})](https://tex.z-dn.net/?f=%5Cdisplaystyle%203.77%20%5C%20mol%20%5C%20K_3N%28%5Cfrac%7B131.31%20%5C%20g%20%5C%20K_3N%7D%7B1%20%5C%20mol%20%5C%20K_3N%7D%29)
- Multiply/Divide:
![\displaystyle 495.039 \ g \ K_3N](https://tex.z-dn.net/?f=%5Cdisplaystyle%20495.039%20%5C%20g%20%5C%20K_3N)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
495.039 g K₃N ≈ 495 g K₃N