Answer:
where's the question... ?
Explanation:
The basis for classifying changes in matter into physical and chemical change is to see if a material is altered after going through a process.
In a physical change only the state of matter is usually altered especially its form or shape.
Chemical change alters a substance by producing new kinds that are totally different from it.
- In a chemical change, new kinds of matter are usually formed.
- Such changes are usually irreversible.
- Change of state is a reversible process.
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Balancing the reaction is done to obey the law of nature, particularly, the Law of Definite Proportions. The concept is, the amount of the same element before and after the reaction must be the same. This is actually a redox reaction.
Oxidation half-reaction: Zn + 4 OH⁻ → Zn(OH)₄²⁻ + 2 e-
Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻
Adding both reaction, we get the overall complete balanced equation:
<span>4Zn + NO</span>₃⁻ + 6 H₂O + 7 OH⁻ → 4 Zn(OH)₄²⁻ + NH₃
Thus, the charge in the product side is 4*-2 = <em>-8</em>.
Answer:
The correct answer is B.
Explanation:
Heterogeneous equilibrium is that in which reagents and products are present in more than one phase.
When the reaction is carried out in a closed container, three equilibrium phases are present: solid magnesium oxide, solid magnesium sulfate and gaseous sulfur trioxide.
Hence, the equilibrium contant is given by:
![K=\frac{[MgSO_4]}{[MgO][SO_3]} =\frac{1}{[SO_3]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BMgSO_4%5D%7D%7B%5BMgO%5D%5BSO_3%5D%7D%20%3D%5Cfrac%7B1%7D%7B%5BSO_3%5D%7D)
The concentrations in the equilibrium equation are the relationships of the real concentrations between the concentrations in the standard state. Since the standard state of a pure solid is the pure solid itself, the ratio of concentrations for a pure solid is equal to one.
Now, we analyse each statement:
I) As the reaction is endothermic (ΔH>0), increasing the temperature shifts the balance to the right because excess heat will be used to form more products.
II) Increasing the volume will decrease the concentration of SO₃, so Q>K and then this shifts the balance to the left.
III) As it is a heterogeneous balance, adding MgO will not affect the balance.
IV) Removing SO3 will decrease its concentration and therefore the reaction equilibrium will shift to the left.
Compounds often differ from elements.