D. The redox reaction is reversed lol..............
Answer:
1.48 M
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
Mg + H2SO4 —> MgSO4 + H2
Step 2:
Determination of the number of mole of Mg in 80.0 mL of 0.200 M Mg solution. This is illustrated below:
Molarity of Mg = 0.200 M
Volume of solution = 80 mL = 80/1000 = 0.08L
Mole of Mg =?
Molarity = mole /Volume
0.2 = mole /0.08
Mole = 0.2 x 0.08
Mole of Mg = 0.016 mole.
Step 3:
Determination of the number of mole of H2SO4 that reacted. This is illustrated below:
Mg + H2SO4 —> MgSO4 + H2
From the balanced equation above,
1 mole of Mg reacted with 1 mole of H2SO4.
Therefore, 0.016 mole of Mg will also react with 0.016 mole of H2SO4.
Step 4:
Determination of the concentration of the acid.
Mole of H2SO4 = 0.016 mole.
Volume of acid solution = 10.8 mL = 10.8/1000 = 0.0108 L
Molarity =?
Molarity = mole /Volume
Molarity = 0.016/0.0108
Molarity of the acid = 1.48 M
Therefore, the concentration of acid is 1.48 M
Answer:
100% pea plants will be with green pod and with round seeds.
Explanation:
As per the question given, a homozygous pea plant having green pod (gg) and round seeds (WW) is crossed with a pea plant having homozygous green pod (gg) and heterozygous round seeds(Ww). A pea plant homozygous for green pod and round seeds (ggWW) will produce one type of gametes having alleles (gW), whereas, a pea plant homozygous for green pod and heterozygous for round seeds(ggWw) will produces two type of gametes having alleles gW and gw. On crossing, phenotypically, they will produce all pea plants with green pod and round seeds. But genotypically, 50% of green pod pea plants with homozygous round seeds and 50% of green pod pea plants with heterozygous round seeds.
Answer:
852g
Explanation:
From the question given, we obtained the following information:
Molarity = 3M
Volume = 2L
Mole =?
First, we need to find the number of mole of Na2SO4 present in 2L of the solution. This is achieved by doing the following:
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 3 x 2 = 6moles
Next, we'll find the molar mass of Na2SO4, as illustrated below:
Molar Mass of Na2SO4 = (23x2)+32+(16x4) = 46 + 32 + 64 = 142g/mol
Recall:
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass = 6 x 142 = 852g
Honestly, I could think of at least 3 chemistry principles relating to this context. That would be the latent energy, intermolecular forces and melting point depression. They are actually related to each other. Pure solid melt at a very low range of melting point. The latent energy is the energy gained at a constant temperature to convert the solid into liquid form. Hence, an impure solid would have a wider range because of the varying type of intermolecular forces. This would lead to melting point depression where impure solid melt at lower temperatures than pure substances. However, they would still have a wide range. So, it is safe to say that pure solid have meting points, while impure solids have melting ranges.
