Answer:
Explanation:
Raoult's law is a tool that allows to determine vapour pressure of solutions. The formula is:
<em>(1)</em>
Where
P is Pressure of solution and solvent and X is mole fraction.
Moles of solute and solvent are:
Biphenyl:
11.5g×(1mol /154.21g) = <em>0.0746mol</em>
Benzene
31.9g×(1mol /78.11g) = <em>0.408mol</em>
Mole fraction of benzene is:
= <em>0.846</em>
Replacing in (1):
I hope it helps!
we will use the root mean squared speed of oxygen formula
v= (3RT) / M
T= vM/3R
where
v =1.12x104 m/s; velocity
R= (8.31447 kg m2 s-2 K-1 mol-1) gas constant
M = 0.0319988 kg/mol; molar mass of oxygen
substituting the given values, we will get
T(K)= 14.37K or -258.78 C
Oxygen molecules speed of 1.12x104 m/s is at temperature -258.78C.
Answer:
Explanation:
Use the periodic table to identify the noble gas that would be included in the noble-gas notation for each of the following elements.
Si:
Fr:
Hg:
V:
Answer:
3.50*10^-11 mol3 dm-9
Explanation:
A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.
Ag2C2O4 --> 2Ag+ + C2O4 2-
So Ksp = [Ag+]^2 * [C2O42-]
In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.
So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)
= 3.50*10^-11 mol3 dm-9
