3 years ago

Need Answer Quick

Chemistry

2 answers:

Mkey [24]3 years ago

7 0

Answer:

Electrons

Explanation:

Vilka [71]3 years ago

4 0

Answer:

Electrons

Explanation:

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Luba_88 [7]

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nucleus

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4 years ago

The rate constant for a certain reaction is k = 4.50×10−3 s−1 . If the initial reactant concentration was 0.400 M, what will the

SIZIF [17.4K]

Answer: The concentration of reactant after the given time is 0.0205 M

Explanation:

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $4.50\times 10^{-3}s^{-1}$

t = time taken for decay process = 11.0 min = 660 s (Conversion factor: 1 min = 60 s)

$[A_o]$ = initial amount of the reactant = 0.400 M

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$4.50\times 10^{-3}s^{-1}=\frac{2.303}{660s}\log\frac{0.400}{[A]}$

$[A]=0.0205M$

Hence, the concentration of reactant after the given time is 0.0205 M

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3 years ago

A sample of gas has a volume of 125mL at 6.0 atm pressure. What will the new volume in mL be of the pressure is decreased to 0.2

Rasek [7]

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levacccp [35]

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g100num [7]

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Hope it will help you

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