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Delvig [45]
3 years ago
10

Which of the following acids (listed with pKa values) and their conjugate base would form a buffer with a pH of 8.10?

Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
7 0

Answer:

(C) HClO, pKa = 7.54

Explanation:

A buffer is a solution that can resist abrupt changes in pH when acids or bases are added. It is formed by two components:

  • A weak acid and its conjugate base.
  • A weak base and its conjugate acid.

In this case, acid and base are defined according to Bronsted-Löwry theory, which states that acids are substances that <em>release H⁺</em> and bases are substances that <em>accept H⁺. </em>Therefore, when an acid loses an H⁺ transforms into its conjugated base. For example, HF/F⁻ is a conjugate acid-base pair.

In buffers, when an acid is added, it reacts with the base to diminish its amount:

F⁻ + H⁺ ⇄ HF

Also in buffers, when a base is added, it reacts with the acid to diminish its amount:

HF + OH⁻ = F⁻ + H₂O

The optimum pH range of work of a buffer system (known as buffer range) is between 1 unit less and 1 unit more of pH than its pKa.

So, the buffer formed by HClO/ClO⁻ works optimally in the pH range 6.54-8.54. Since pH = 8.10 is in that interval, this would be the optimal choice.

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damaskus [11]

Answer:

pH = 6.5

Explanation:

Given data:

pH of substance = ?

[OH⁻] concentration = 3.2×10⁻⁸

Solution:

pOH = -log[OH⁻]

pOH = -log[3.2×10⁻⁸]

pOH = 7.5

we know that,

pH + pOH = 14

pH = 14- pOH

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3 years ago
A compound consists of 75% magnesium and 25% oxygen. Find the empirical formula.
laila [671]
<h2>Answer:</h2>

% Composition of elements:

  • Magnesium = 75%
  • Oxygen = 25%

Atomic mass of given elements:

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Now, divide % composition by Atomic mass:

\footnotesize\implies Mg = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{75}{24}  =  \bf 3.125

\footnotesize\implies O = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{25}{16}  =  \bf 1.5625

Simplest Ratio:

\footnotesize\implies Mg  =  \dfrac{3.125}{1.5625}  = 2

\footnotesize\implies O  =  \dfrac{1.5625}{1.5625} = 1

Empirical Formula:

\footnotesize\implies \underline{ \boxed{ \red{ \bf Empirical \:  Formula = Mg_2O}}}

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Answer:

pH = 1.683

Explanation:

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