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Sergeeva-Olga [200]
4 years ago
9

Did I balance this equation correctly

Chemistry
1 answer:
11111nata11111 [884]4 years ago
7 0
Yep! I typed your equation into this website"http://www.endmemo.com/chem/balancer.php" and it said it was balanced
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A Question 2 (2 points) Retake question
Ksivusya [100]

Answer:

3.3765 Mol O2

Explanation:

There is no work for this problem

3 0
3 years ago
Can anyone help me ASAP
harkovskaia [24]

Answer: Balance, multiply, find ratio

Explanation:

Balance the equation to be able to multiply correctly and accurately, multiply, and this will give you the molar ratio

5 0
3 years ago
How many grams of O₂ are required to react completely with 14.6 g of Na to form sodium oxide, Na₂O?
Bad White [126]

The balanced chemical reaction is :

O_2 + 4Na \ -> \ 2Na_2O

Number of moles of Na, n = \dfrac{14.6}{23} = 0.635 \  mol .

Now, from balance chemical reaction we can see that 1 mole of oxygen reacts with 4 moles of sodium.

So, number of moles of oxygen are :

n = \dfrac{0.635}{4}\  mole

So, amount of oxygen required is :

m = \dfrac{0.635 \times 32}{4}\  gm\\\\m = 5.08 \ gm

Therefore, 5.08 gram of oxygen will react with 14.6 gram of sodium.

7 0
3 years ago
How can we identify that the absorption of heat has occurred?​
loris [4]

Answer:

rise in temperature and the effect it has on our global weather patterns

5 0
3 years ago
For the reaction given below, the frequency factor A is 8.7 1012 s−1 and the activation energy is 63 kJ/mol. NO(g) + O3(g) → NO2
Alex73 [517]

Answer:

K(70°C) = 2213.376 s-1

Explanation:

balanced reaction:

  • NO(g) + O3(g) → NO2(g) + O2(g)

∴ Ea = 63 KJ/mol

∴ A = 8.7 E12 s-1

∴ T = 70°C ≅ 343 K

Arrhenius eq:

  • K(T) = Ae∧(- Ea/RT)

∴ R = 8.314 E-3 KJ/K.mol

⇒ K(70°C) = (8.7 E12 s-1)e∧[-(63)/(8.314 E-3)(343)]

⇒ K(70°C) = (8.7 E12 s-1)*(2.5444 E-10)

⇒ K(70°C) = 2213.376 s-1

6 0
3 years ago
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