Did I balance this equation correctly
1 answer:
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Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is kg.
Explanation:
We know that relation between heat energy and specific heat is as follows.
q =
As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.
Mass of water = Volume × Density
=
= 400,000 kg
or, = g (as 1 kg = 1000 g)
Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.
= 305 K - 273 K
= 32 K
Now, putting the given values into the above formula and calculate the heat energy as follows.
q =
=
= J
or, = kJ
According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of kJ is calculated as follows.
Mass =
= kg
Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is kg.