Answer:
![V_2 = 0.125 m^3](https://tex.z-dn.net/?f=V_2%20%3D%200.125%20m%5E3)
Work done = = 5 kJ
Explanation:
Given data:
volume of nitrogen ![v_1 = 0.08 m^3](https://tex.z-dn.net/?f=%20v_1%20%3D%200.08%20m%5E3)
![P_1 = 150 kPa](https://tex.z-dn.net/?f=P_1%20%3D%20150%20kPa)
![T_1 = 200 degree celcius = 473 Kelvin](https://tex.z-dn.net/?f=T_1%20%3D%20200%20degree%20celcius%20%3D%20473%20Kelvin)
![P_2 = 80 kPa](https://tex.z-dn.net/?f=P_2%20%3D%2080%20kPa)
Polytropic exponent n = 1.4
![\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}](https://tex.z-dn.net/?f=%5Cfrac%7BT_2%7D%7BT_1%7D%20%3D%20%5B%5Cfrac%7BP_2%7D%7BP_1%7D%5D%5E%7B%5Cfrac%7Bn-1%7D%7Bn%7D)
putting all value
![\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}](https://tex.z-dn.net/?f=%5Cfrac%7BT_2%7D%7B473%7D%20%3D%20%5B%5Cfrac%7B80%7D%7B150%7D%5D%5E%7B%5Cfrac%7B1.4-1%7D%7B1.4%7D)
![\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS](https://tex.z-dn.net/?f=%5Cfrac%7BT_2%7D%20%3D%20395.23%20K%20%3D%20122.08%20DEGREE%20%5C%20CELCIUS)
polytropic process is given as
![P_1 V_1^n = P_2 V_2^n](https://tex.z-dn.net/?f=P_1%20V_1%5En%20%3D%20P_2%20V_2%5En)
![150\times 0.08^{1.4} = 80 \times V_2^{1.4}](https://tex.z-dn.net/?f=150%5Ctimes%200.08%5E%7B1.4%7D%20%3D%2080%20%5Ctimes%20V_2%5E%7B1.4%7D)
![V_2 = 0.125 m^3](https://tex.z-dn.net/?f=V_2%20%3D%200.125%20m%5E3)
work done ![= \frac{P_1 V_1 -P_2 V_2}{n-1}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7BP_1%20V_1%20-P_2%20V_2%7D%7Bn-1%7D)
![= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B150%20%5Ctimes%200.8%20-%2080%20%5Ctimes%200.125%7D%7B1.4-1%7D)
= 5 kJ
Explanation:
The expansion of the universe is the increase in distance between any two given ... Metric expansion is a key feature of Big Bang cosmology, is modeled mathematically with the ...
Answer:
Do u have a picture of the graph?
Explanation:
I can solve it with refraction
Question:
A spaceship enters the solar system moving toward the Sun at a constant speed relative to the Sun. By its own clock, the time elapsed between the time it crosses the orbit of Jupiter and the time it crosses the orbit of Mars is 35.0 minutes
How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the orbit of Mars is 12.6 light-minutes.
Answer:
S = 5.508 × 10¹¹m
V = 2.62 × 10⁸ m/s
Explanation:
The radius of the orbit of Jupiter, Rj is 43.2 light-minutes
radius of the orbit of Mars, Rm is 12.6 light-minutes
Distance travelled S = (Rj - Rm)
= 43.2 - 12.6 = 30.6 light- minutes
= 30.6 × (3 ×10⁸m/s) × 60 s
= 5.508 × 10¹¹m
time = 35mins = (35 × 60 secs)
= 2100 secs
speed = distance/time
V = 5.508 × 10¹¹m / 2100 s
V = 2.62 × 10⁸ m/s