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Margaret [11]
3 years ago
7

3.00 kg block moving 2.09 m/s right hits a 2.22 kg block moving 3.92 m/s left. afterwards, the 3.00 kg block moves 1.71 m/s left

. find the velocity of the 2.22 kg block afterwards
Physics
1 answer:
Leviafan [203]3 years ago
7 0

Momentum is conserved, so the total momentum before collision is equal to the total momentum after collision. Take the right direction to be positive. Then

(3.00 kg) (2.09 m/s) + (2.22 kg) (-3.92 m/s) = (3.00 kg) (-1.71 m/s) + (2.22 kg) <em>v</em>

where <em>v</em> is the velocity of the 2.22 kg block after collision. Solve for <em>v</em> :

6.27 kg•m/s - 8.70 kg•m/s = -5.13 kg•m/s + (2.22 kg) <em>v</em>

(2.22 kg) <em>v</em> = 2.70 kg•m/s

<em>v</em> = (2.70 kg•m/s) / (2.22 kg)

<em>v</em> ≈ 1.22 m/s

i.e. a velocity of about 1.22 m/s to the right.

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Answer:

Explanation:

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W=-∫2x³dx from x=0 to x=D

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W=-2(D⁴/4-0/4)

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Answer:

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Now, we know that the equivalent capacitance of the two parallel connected capacitors is given by:

C_{eq} = C + C' = 2.0 + 4.0 = 6.0\micro F = 6.0\times 10^{- 6} F

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When objects exchange charge, why do we say it's the negative charge that moves and not the positive?
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The electron has a negative charge. The proton has a positive charge. And the neutron has no charge, so it is neutral. While the atom has the same number of protons and electrons, it will not be electrically charged.

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3 years ago
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Answer:

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Explanation:

From the question we are told that

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     Where \rho_w is the density of freshwater which has a constant value

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     Let the final height of the device under the water be  =  h_f

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              = \frac{g A \rho}{2}  [h^2 - h_f^2]

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Substituting values

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